A wire of length 0.50 m carries a current of 3.0 A. The wire is at right angles to a magnetic field of magnetic flux density 0.20 T0.20\ \text{T}0.20 T.
Use the equation: force=magnetic flux density×current×length\text{force} = \text{magnetic flux density} \times \text{current} \times \text{length}force=magnetic flux density×current×length
What is the force on the wire?
1.2 N1.2\ \text{N}1.2 N
3.7 N3.7\ \text{N}3.7 N
0.033 N0.033\ \text{N}0.033 N
0.30 N0.30\ \text{N}0.30 N
48 exam-style questions on OCR GCSE Physics 4.2 Uses of magnetism, covering 4.2.1 The motor effect, 4.2.2 Fleming's left-hand rule, 4.2.3 The force on a current-carrying conductor, 4.2.4 The electric motor, 4.2.5 Electromagnetic induction, 4.2.6 Alternators and dynamos, 4.2.7 How transformers work, 4.2.8 Transformer turns ratio, 4.2.9 Potential differences and turns in transformers, and 4.2.10 Microphones, loudspeakers and headphones. Each one has a worked solution and a mark scheme showing where the marks go.