4.3.1 Sound waves, vibrations and the human ear
From sound to hearing
Sound wave
A longitudinal mechanical wave produced by a vibrating source and carried through a medium as a series of compressions and rarefactions.
- A vibrating source pushes and pulls nearby particles in a medium.
- The particles oscillate parallel to the direction of energy transfer, producing alternating compressions and rarefactions.
- The particles transfer the disturbance to neighbouring particles, so energy travels through the medium without the medium moving overall.
- Sound cannot travel through a vacuum because there are no particles to pass on the vibration.
Sound and solid vibrations
Frequency
The number of complete waves or oscillations passing a point each second.
- When sound reaches a solid surface, changing pressure exerts an alternating force on it and can make it vibrate.
- A vibrating solid can also push and pull the surrounding medium, converting its vibration into a sound wave.
- The frequency of the sound wave matches the frequency of the source vibration.
- A larger vibration amplitude usually produces a sound wave with a larger amplitude and a greater intensity.
The human ear
- The pinna collects sound and channels it through the ear canal.
- Pressure variations make the eardrum vibrate at the sound frequency.
- The three ossicles transfer the vibration through the middle ear and increase the pressure applied to the oval window.
- Movement at the oval window produces pressure waves in the fluid of the cochlea.
- Different regions of the cochlea respond most strongly to different frequencies.
- Sensory hair cells bend and convert the mechanical disturbance into electrical impulses.
- The auditory nerve carries these impulses to the brain, where they are interpreted as sound.
A limited frequency range
- A structure responds effectively only over a limited frequency range because its mass, stiffness and damping affect how easily it can vibrate.
- At some frequencies the response amplitude is large, while very low or very high frequencies produce a weaker response.
- The combined response of the eardrum, ossicles, cochlea and hair cells limits normal human hearing to roughly 20 Hz20\ \text{Hz}20 Hz to 20 000 Hz20\,000\ \text{Hz}20000 Hz.
- The upper limit usually falls with age and after exposure to intense sound.
Linking pitch to vibration
- A loudspeaker cone completes 750750750 vibrations in 0.50 s0.50\ \text{s}0.50 s.
- Its frequency is f=7500.50=1500 Hzf=\dfrac{750}{0.50}=1500\ \text{Hz}f=0.50750=1500 Hz.
- The sound wave and the eardrum vibrate at 1500 Hz1500\ \text{Hz}1500 Hz, so the frequency is within the normal human hearing range.
- For an ear question, follow the energy transfer in order: sound wave, eardrum, ossicles, oval window, cochlear fluid, hair cells, auditory nerve.
- Use the word converts only when the form of the disturbance changes, such as a mechanical vibration becoming an electrical impulse.
- Do not say that air particles travel from the source to the ear; they oscillate about fixed positions.
- Do not confuse frequency with amplitude: frequency affects pitch, whereas amplitude is linked to loudness.
- How does a vibrating source produce a sound wave?
- Why can sound not travel through a vacuum?
- What sequence transfers a vibration from the eardrum to the cochlea?
- How do hair cells contribute to hearing?
- Why does the ear work over only a limited frequency range?
4.3.2 Ultrasound and infrasound
Frequencies beyond hearing
Ultrasound
Sound with a frequency greater than 20 000 hertz, above the upper limit of normal human hearing.
Infrasound
Sound with a frequency less than 20 hertz, below the lower limit of normal human hearing.
- Sound from about 20 Hz20\ \text{Hz}20 Hz to 20 000 Hz20\,000\ \text{Hz}20000 Hz lies within the typical hearing range of a young person.
- The limits describe frequency, not loudness, so an intense ultrasound wave remains inaudible to humans.
- Ultrasound and infrasound are mechanical waves and therefore require a medium.
Wave properties
- For every sound wave, speed, frequency and wavelength are linked by v=fλv=f\lambdav=fλ.
- At a fixed sound speed, ultrasound has a shorter wavelength than audible sound, while infrasound has a longer wavelength.
- Short wavelengths can detect small details, which is useful for imaging and flaw detection.
- Long wavelengths can travel around large obstacles and may propagate over very long distances.
Producing and detecting ultrasound
- A rapidly alternating potential difference can make a piezoelectric crystal change shape and vibrate.
- The vibrating crystal produces ultrasound at the driving frequency.
- Returning ultrasound makes the crystal vibrate and produces an alternating potential difference, so the same type of transducer can act as a detector.
Sources of infrasound
- Large, slow vibrations can produce infrasound, including earthquakes, volcanic activity, ocean waves and large machinery.
- Some animals can produce or detect frequencies outside the human hearing range.
- Detecting a wave does not mean a person hears it; electronic sensors can convert it into a measurable electrical signal.
Comparing wavelengths
- Sound travels at 340 m s−1340\ \text{m s}^{-1}340 m s−1 in air.
- For ultrasound at 40 000 Hz40\,000\ \text{Hz}40000 Hz, λ=34040 000=8.5×10−3 m\lambda=\dfrac{340}{40\,000}=8.5\times10^{-3}\ \text{m}λ=40000340=8.5×10−3 m.
- For infrasound at 10 Hz10\ \text{Hz}10 Hz, λ=34010=34 m\lambda=\dfrac{340}{10}=34\ \text{m}λ=10340=34 m.
- The infrasound wavelength is much larger than the ultrasound wavelength.
- Classify a sound by comparing its frequency with the two numerical boundaries and include the unit hertz.
- When explaining a use, link frequency to wavelength and then to the required effect, such as resolving small structures.
- Do not write that ultrasound is sound above the loudness threshold; ultrasound is defined only by frequency.
- Use 20 000 Hz20\,000\ \text{Hz}20000 Hz, not 20 000 kHz20\,000\ \text{kHz}20000 kHz.
- What frequency range defines ultrasound?
- What frequency range defines infrasound?
- Why does ultrasound have a short wavelength in a given medium?
- How can a piezoelectric crystal produce and detect ultrasound?
- Name two natural sources of infrasound.
4.3.3 Uses of ultrasound and infrasound
Uses of high and low frequencies
- Ultrasound and infrasound are useful because their wavelengths, propagation and reflection differ from those of audible sound.
- A complete explanation links the wave property to the way information is obtained.
Sonar
Sonar
A technique that sends ultrasound pulses through water and uses the time for their echoes to return to find the distance to an object or the depth of water.
- A transmitter sends an ultrasound pulse through water.
- The pulse reflects from the seabed, a shoal of fish or another boundary and returns to a detector.
- The measured time is for the outward and return journeys, so the one-way distance is d=vt2d=\dfrac{vt}{2}d=2vt.
- Short pulses and short wavelengths help distinguish nearby objects and provide better detail.
Finding sea depth
- A sonar pulse returns from the seabed after 0.080 s0.080\ \text{s}0.080 s, and sound travels through seawater at 1500 m s−11500\ \text{m s}^{-1}1500 m s−1.
- The total travelled distance is vt=1500×0.080=120 mvt=1500\times0.080=120\ \text{m}vt=1500×0.080=120 m.
- The water depth is d=1202=60 md=\dfrac{120}{2}=60\ \text{m}d=2120=60 m.
Foetal scanning
- A transducer sends pulses of ultrasound into the body through coupling gel, which reduces reflection at the skin.
- At boundaries between tissues, some ultrasound is reflected while the rest continues deeper.
- The time delay gives the depth of a boundary, and the echo strength helps distinguish different tissues.
- A computer combines many echoes to form an image of the foetus.
- Ultrasound is non-ionising, so it does not carry the ionisation risk associated with X-rays, although exposure is still kept as low as needed.
Exploring the Earth
- Earthquakes produce seismic waves with very low frequencies, including infrasound and vibrations that pass through the Earth.
- Seismic waves change speed, refract and reflect at boundaries between layers.
- Detectors around the Earth record arrival times and wave paths.
- Differences in speed and the presence of shadow zones provide evidence for internal layers, including the mantle and core.
- Different seismic wave types behave differently in solids and liquids, which helps identify whether a layer is solid or liquid.
- For an echo calculation, state that the measured time covers two journeys before dividing by 222.
- For a scanning explanation, link each echo's time delay to depth and its amplitude to the nature of the boundary.
- For the Earth's core, refer to changes in speed, refraction, reflection and detected arrival patterns.
- Do not describe a foetal scan as an X-ray image; it is formed from reflected ultrasound pulses.
- Do not forget the factor of 222 in pulse-echo distance calculations.
- How does sonar determine the distance to an object?
- Why is coupling gel used in an ultrasound scan?
- What information is obtained from echo time and echo amplitude?
- How do seismic-wave paths provide evidence about the Earth's interior?
- Why must pulse-echo travel time be divided by two?
4.3.4 Sound waves passing between media
Sound crossing a boundary
Medium
A substance whose particles pass on the oscillations of a mechanical wave, such as sound, from one place to another.
- When sound crosses from one medium into another, its speed usually changes because particle spacing, stiffness and density affect how quickly vibrations are transferred.
- The source remains unchanged, so the frequency is unchanged at the boundary.
- The wavelength changes because v=fλv=f\lambdav=fλ.
Linking speed and wavelength
- If sound speed increases while frequency stays constant, wavelength increases.
- If sound speed decreases while frequency stays constant, wavelength decreases.
- The ratio is v2v1=λ2λ1\dfrac{v_2}{v_1}=\dfrac{\lambda_2}{\lambda_1}v1v2=λ1λ2 because fff is the same on both sides.
- The period T=1fT=\dfrac{1}{f}T=f1 also remains unchanged.
Direction and transmission
- Sound arriving at an angle may refract because one side of the wavefront changes speed first.
- If sound speeds up, it bends away from the normal; if it slows down, it bends towards the normal.
- Sound arriving along the normal changes speed and wavelength without changing direction.
- At the same boundary, some sound energy may be reflected and some may be absorbed, so the transmitted amplitude can be smaller.
Sound in different materials
- Sound generally travels faster in solids than in liquids and faster in liquids than in gases because the restoring forces between particles are stronger in more rigid media.
- Density alone is not a complete rule because wave speed depends on both density and stiffness.
- A change in wave speed does not mean the sound source has changed pitch because pitch is linked to frequency, which remains constant.
Sound entering water
- A sound wave of frequency 500 Hz500\ \text{Hz}500 Hz travels at 340 m s−1340\ \text{m s}^{-1}340 m s−1 in air and 1500 m s−11500\ \text{m s}^{-1}1500 m s−1 in water.
- In air, λ1=340500=0.68 m\lambda_1=\dfrac{340}{500}=0.68\ \text{m}λ1=500340=0.68 m.
- In water, λ2=1500500=3.0 m\lambda_2=\dfrac{1500}{500}=3.0\ \text{m}λ2=5001500=3.0 m.
- The frequency stays at 500 Hz500\ \text{Hz}500 Hz while speed and wavelength both increase.
- For a three-quantity question, state each result explicitly: speed changes, frequency stays constant and wavelength changes in the same direction as speed.
- Support the relationship with v=fλv=f\lambdav=fλ and keep units consistent.
- Do not state that frequency changes because the medium changes; the source sets frequency.
- Do not use density alone to predict sound speed because stiffness also affects the result.
- Which sound-wave quantity remains unchanged at a boundary?
- What happens to wavelength when sound speed increases?
- Why can sound refract when it enters a new medium at an angle?
- Why is density alone insufficient to predict sound speed?
- How are v2/v1v_2/v_1v2/v1 and λ2/λ1\lambda_2/\lambda_1λ2/λ1 related?
