Forces that make objects turn
Definition
Pivot
A pivot is the fixed point about which an object turns.
Definition
Line of action
The line of action of a force is the straight line drawn through the point where the force acts, extended in the direction in which the force acts.
- A force does not always move an object in a straight line, because an object held at one fixed point will turn about that point instead.
- That fixed point is the pivot, and identifying it is the first step in every turning question.
- Pushing the handle of a door swings the door about its hinges, which act as the pivot.
- Pulling on a spanner turns the nut about the centre of the nut.
- Pushing down on one end of a seesaw turns the plank about the central support.
- Pushing a bicycle pedal turns the crank about the centre of the chain wheel.
- Turning a tap, a steering wheel, a wheelbarrow handle or the lid of a jar are the same idea applied to different pivots.
- Whether a force actually turns the object depends on its line of action, the straight line drawn through the force in the direction in which it acts.
- If the line of action passes through the pivot, the force produces no turning effect at all, because the distance from the pivot to that line is zero.
- Pushing a door exactly along the line through its hinges is the everyday version of this, because the door will not move however hard it is pushed.
Calculating the moment of a force
Definition
Moment of a force
The moment of a force is the turning effect of that force about a pivot, equal to the force multiplied by the distance normal to the direction of the force.
- The size of the turning effect is called the moment of a force.
- The equation is moment of a force=force×distance normal to the direction of the force\text{moment of a force} = \text{force} \times \text{distance normal to the direction of the force}moment of a force=force×distance normal to the direction of the force, written in symbols as M=F dM = F\,dM=Fd.
- The symbols mean the following.
- MMM is the moment, measured in newton metres, N m\text{N m}N m.
- FFF is the force, measured in newtons, N\text{N}N.
- ddd is the distance from the pivot measured normal to the direction of the force, in metres, m\text{m}m.
- Normal means at 90∘90^\circ90∘, so ddd is the perpendicular distance from the pivot to the line of action of the force, and not simply the length of the handle.
- When the force is applied at right angles to a spanner, that perpendicular distance is the whole length from the nut to the hand, which is why pushing at 90∘90^\circ90∘ is the most effective way to use one.
- Tilting the force away from 90∘90^\circ90∘ shortens the perpendicular distance, so the moment falls even though the size of the force has not changed.
- The moment reaches zero when the force acts straight along the handle, because the line of action then runs through the pivot.
- There are two ways to produce a larger moment.
- Apply a larger force.
- Apply the same force at a greater perpendicular distance from the pivot.
- This is why a long spanner loosens a stiff nut that a short one cannot, and why a door handle is fitted at the edge furthest from the hinges.
- The equation rearranges to F=MdF = \dfrac{M}{d}F=dM and to d=MFd = \dfrac{M}{F}d=FM, which are the forms needed when the moment is the quantity given.
- Distances must be converted into metres before substituting, so 30 cm30\ \text{cm}30 cm becomes 0.30 m0.30\ \text{m}0.30 m.
- A moment is written in N m\text{N m}N m and never in joules, because a moment is a turning effect and not an amount of energy transferred.
Example
Moment of a force on a spanner
- A mechanic pushes at right angles to a spanner with a force of 45 N45\ \text{N}45 N, at a distance of 30 cm30\ \text{cm}30 cm from the centre of the nut.
- Convert the distance into metres, so 30 cm=0.30 m30\ \text{cm} = 0.30\ \text{m}30 cm=0.30 m.
- State the equation, M=F dM = F\,dM=Fd.
- Substitute the values, M=45 N×0.30 mM = 45\ \text{N} \times 0.30\ \text{m}M=45 N×0.30 m.
- The moment of the force is 13.5 N m13.5\ \text{N m}13.5 N m.
Example
Finding the force needed for a given moment
- A bolt needs a moment of 24 N m24\ \text{N m}24 N m before it will turn, and the spanner is gripped 0.40 m0.40\ \text{m}0.40 m from the centre of the bolt.
- Rearranging M=F dM = F\,dM=Fd gives F=MdF = \dfrac{M}{d}F=dM.
- Substituting gives F=240.40F = \dfrac{24}{0.40}F=0.4024.
- The force needed is 60 N60\ \text{N}60 N, applied at right angles to the spanner.
- Gripping the spanner at 0.80 m0.80\ \text{m}0.80 m instead would halve this to 30 N30\ \text{N}30 N, because the moment required stays the same.
Common Mistake
- Do not confuse moment with momentum, because a moment is a turning effect measured in N m\text{N m}N m while momentum is mass multiplied by velocity in kg m/s\text{kg m/s}kg m/s.
- Do not use the full length of a spanner or a door as ddd unless the force is applied at the far end and at right angles to it.
- Do not leave a distance in centimetres, because multiplying newtons by centimetres gives an answer one hundred times too large.
- Do not give a moment in joules, since a moment is not an energy transfer even though both units come from a newton and a metre.
Exam technique
Setting out a moment calculation
- Write M=F dM = F\,dM=Fd before substituting anything, because the equation itself often carries a mark.
- Mark the pivot on the diagram, then measure the perpendicular distance from it to the line of action of the force.
- Convert every distance into metres on its own line, so that a unit slip is easy to spot.
- Write the unit N m\text{N m}N m next to the final number rather than leaving the answer bare.
- In a description question, name the pivot and then say that the moment increases when either the force or the perpendicular distance increases.
Self review
- State what is meant by the moment of a force.
- Write the equation linking moment, force and distance, and give the unit of each quantity.
- Explain what the word normal means in the phrase distance normal to the direction of the force.
- Explain why a force whose line of action passes through the pivot produces no turning effect.
- Calculate the moment produced by a force of 20 N20\ \text{N}20 N acting at right angles to a lever at 0.25 m0.25\ \text{m}0.25 m from the pivot.