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9.2.1 Rotational effects of forces and moments

Forces that make objects turn

Definition

Pivot

A pivot is the fixed point about which an object turns.

Definition

Line of action

The line of action of a force is the straight line drawn through the point where the force acts, extended in the direction in which the force acts.

  1. A force does not always move an object in a straight line, because an object held at one fixed point will turn about that point instead.
  2. That fixed point is the pivot, and identifying it is the first step in every turning question.
  3. Pushing the handle of a door swings the door about its hinges, which act as the pivot.
  4. Pulling on a spanner turns the nut about the centre of the nut.
  5. Pushing down on one end of a seesaw turns the plank about the central support.
  6. Pushing a bicycle pedal turns the crank about the centre of the chain wheel.
  7. Turning a tap, a steering wheel, a wheelbarrow handle or the lid of a jar are the same idea applied to different pivots.
  8. Whether a force actually turns the object depends on its line of action, the straight line drawn through the force in the direction in which it acts.
  9. If the line of action passes through the pivot, the force produces no turning effect at all, because the distance from the pivot to that line is zero.
  10. Pushing a door exactly along the line through its hinges is the everyday version of this, because the door will not move however hard it is pushed.

Calculating the moment of a force

Definition

Moment of a force

The moment of a force is the turning effect of that force about a pivot, equal to the force multiplied by the distance normal to the direction of the force.

  1. The size of the turning effect is called the moment of a force.
  2. The equation is moment of a force=force×distance normal to the direction of the force\text{moment of a force} = \text{force} \times \text{distance normal to the direction of the force}moment of a force=force×distance normal to the direction of the force, written in symbols as M=F dM = F\,dM=Fd.
  3. The symbols mean the following.
    1. MMM is the moment, measured in newton metres, N m\text{N m}N m.
    2. FFF is the force, measured in newtons, N\text{N}N.
    3. ddd is the distance from the pivot measured normal to the direction of the force, in metres, m\text{m}m.
  4. Normal means at 90∘90^\circ90∘, so ddd is the perpendicular distance from the pivot to the line of action of the force, and not simply the length of the handle.
  5. When the force is applied at right angles to a spanner, that perpendicular distance is the whole length from the nut to the hand, which is why pushing at 90∘90^\circ90∘ is the most effective way to use one.
  6. Tilting the force away from 90∘90^\circ90∘ shortens the perpendicular distance, so the moment falls even though the size of the force has not changed.
  7. The moment reaches zero when the force acts straight along the handle, because the line of action then runs through the pivot.
  8. There are two ways to produce a larger moment.
    1. Apply a larger force.
    2. Apply the same force at a greater perpendicular distance from the pivot.
  9. This is why a long spanner loosens a stiff nut that a short one cannot, and why a door handle is fitted at the edge furthest from the hinges.
  10. The equation rearranges to F=MdF = \dfrac{M}{d}F=dM​ and to d=MFd = \dfrac{M}{F}d=FM​, which are the forms needed when the moment is the quantity given.
  11. Distances must be converted into metres before substituting, so 30 cm30\ \text{cm}30 cm becomes 0.30 m0.30\ \text{m}0.30 m.
  12. A moment is written in N m\text{N m}N m and never in joules, because a moment is a turning effect and not an amount of energy transferred.
Example

Moment of a force on a spanner

  • A mechanic pushes at right angles to a spanner with a force of 45 N45\ \text{N}45 N, at a distance of 30 cm30\ \text{cm}30 cm from the centre of the nut.
  • Convert the distance into metres, so 30 cm=0.30 m30\ \text{cm} = 0.30\ \text{m}30 cm=0.30 m.
  • State the equation, M=F dM = F\,dM=Fd.
  • Substitute the values, M=45 N×0.30 mM = 45\ \text{N} \times 0.30\ \text{m}M=45 N×0.30 m.
  • The moment of the force is 13.5 N m13.5\ \text{N m}13.5 N m.
Example

Finding the force needed for a given moment

  • A bolt needs a moment of 24 N m24\ \text{N m}24 N m before it will turn, and the spanner is gripped 0.40 m0.40\ \text{m}0.40 m from the centre of the bolt.
  • Rearranging M=F dM = F\,dM=Fd gives F=MdF = \dfrac{M}{d}F=dM​.
  • Substituting gives F=240.40F = \dfrac{24}{0.40}F=0.4024​.
  • The force needed is 60 N60\ \text{N}60 N, applied at right angles to the spanner.
  • Gripping the spanner at 0.80 m0.80\ \text{m}0.80 m instead would halve this to 30 N30\ \text{N}30 N, because the moment required stays the same.
Common Mistake
  • Do not confuse moment with momentum, because a moment is a turning effect measured in N m\text{N m}N m while momentum is mass multiplied by velocity in kg m/s\text{kg m/s}kg m/s.
  • Do not use the full length of a spanner or a door as ddd unless the force is applied at the far end and at right angles to it.
  • Do not leave a distance in centimetres, because multiplying newtons by centimetres gives an answer one hundred times too large.
  • Do not give a moment in joules, since a moment is not an energy transfer even though both units come from a newton and a metre.
Exam technique

Setting out a moment calculation

  • Write M=F dM = F\,dM=Fd before substituting anything, because the equation itself often carries a mark.
  • Mark the pivot on the diagram, then measure the perpendicular distance from it to the line of action of the force.
  • Convert every distance into metres on its own line, so that a unit slip is easy to spot.
  • Write the unit N m\text{N m}N m next to the final number rather than leaving the answer bare.
  • In a description question, name the pivot and then say that the moment increases when either the force or the perpendicular distance increases.
Self review
  • State what is meant by the moment of a force.
  • Write the equation linking moment, force and distance, and give the unit of each quantity.
  • Explain what the word normal means in the phrase distance normal to the direction of the force.
  • Explain why a force whose line of action passes through the pivot produces no turning effect.
  • Calculate the moment produced by a force of 20 N20\ \text{N}20 N acting at right angles to a lever at 0.25 m0.25\ \text{m}0.25 m from the pivot.
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9.2.1 Rotational effects of forces and moments Revision Guide

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Revision notes for Edexcel GCSE Physics 9.2.1 Rotational effects of forces and moments: explanations and worked examples.

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