A camera is mounted on a light horizontal boom that can turn about a pivot. The boom is stationary. All the forces shown act vertically downwards.
| Object | Side of pivot | Force | Perpendicular distance from pivot |
|---|---|---|---|
| camera | right | 160 N | 1.20 m |
| motor | right | 80 N | 0.45 m |
| counterweight | left | 400 N | ddd |
Calculate the distance d d\,d from the pivot to the line of action of the counterweight force.
The counterweight is moved 0.12 m closer to the pivot, while the other forces remain unchanged.
Explain how the boom will begin to turn.
102 exam-style questions on Edexcel GCSE Physics 9.2 Moments, covering 9.2.1 Rotational effects of forces and moments, 9.2.2 The principle of moments, and 9.2.3 Levers and gears. Each one has a worked solution and a mark scheme showing where the marks go.