A uniform beam of mass 10 kg and length 3.0 m is resting horizontally in equilibrium on a pivot located 1.0 m from its left-hand end.
Two downward vertical forces are applied: a force of magnitude F1 F_1\,F1 at the far-left end and a force of 40 N at the far-right end, as shown in the diagram below.
Taking the acceleration due to gravity to be g=9.8 m s−2g = 9.8\text{ m s}^{-2}g=9.8 m s−2, what is the value of F1 F_1\,F1 required to maintain the beam in rotational equilibrium?
85 N85\text{ N}85 N
129 N129\text{ N}129 N
227 N227\text{ N}227 N
80 N80\text{ N}80 N