A force is a push or pull. Force is measured in newtons, N.
A force is a vector, which means it has both a size and a direction. So when forces act in opposite directions, you must think about direction, not just add every number together.
Resultant force
The resultant force is the single overall force left after all the forces on an object have been combined, taking their directions into account.
If the resultant force is zero, the forces are balanced. The object either stays still or continues moving at constant velocity. Velocity means speed in a particular direction.
If the resultant force is not zero, the forces are unbalanced, and the object accelerates in the direction of the resultant force.
The diagram shows a trolley with forces acting on it. The upward normal contact force is the support force from the track. Weight is the downward force due to gravity. Friction and drag are forces that oppose motion.

Finding a resultant force
Take right as the positive direction. A 90 N pull acts to the right and 25 N friction acts to the left, so F=90 N−25 NF = 90 \text{ N} - 25 \text{ N}F=90 N−25 N.
Calculate the resultant force: F=65 NF = 65 \text{ N}F=65 N.
The answer is positive, so the resultant force is 65 N to the right. Any acceleration will also be to the right.
Acceleration is the rate of change of velocity. It tells you how quickly velocity changes each second.
Acceleration is measured in metres per second squared, m/s^2, and its symbol is aaa.
You may already know:
a=v−uta = \frac{v-u}{t}a=tv−uwhere uuu is the initial velocity, vvv is the final velocity, and ttt is the time taken.
Calculating acceleration from a velocity change
A cyclist speeds up from 2.0 m/s to 8.0 m/s in 3.0 s, so u=2.0 m/su = 2.0 \text{ m/s}u=2.0 m/s, v=8.0 m/sv = 8.0 \text{ m/s}v=8.0 m/s and t=3.0 st = 3.0 \text{ s}t=3.0 s.
Substitute into the acceleration equation: a=8.0 m/s−2.0 m/s3.0 sa = \frac{8.0 \text{ m/s} - 2.0 \text{ m/s}}{3.0 \text{ s}}a=3.0 s8.0 m/s−2.0 m/s.
Calculate a=2.0 m/s2a = 2.0 \text{ m/s}^2a=2.0 m/s2, so the cyclist’s velocity increases by 2.0 m/s every second.
Newton’s Second Law links the acceleration of an object to two things:
Mass is the amount of matter in an object. It is measured in kilograms, kg. In this topic, mass tells you how difficult it is to change an object’s motion.
Proportional
Two quantities are proportional if changing one by a scale factor changes the other by the same scale factor. The symbol for “is proportional to” is ∝\propto∝.
For a constant mass:
a∝Fa \propto Fa∝FSo if the resultant force doubles, the acceleration doubles.
For a constant resultant force:
a∝1ma \propto \frac{1}{m}a∝m1This means acceleration is inversely proportional to mass. If the mass doubles, the acceleration halves.
Newton’s Second Law in words
The acceleration of an object is proportional to the resultant force acting on it, and inversely proportional to the mass of the object.
The equation you need to recall and apply is:
F=maF = maF=mawhere:
Rearranging F = ma
If acceleration is unknown, use a=Fma = \frac{F}{m}a=mF. If mass is unknown, use m=Fam = \frac{F}{a}m=aF.
Using F = ma with resistive forces
A car has a driving force of 2500 N forwards and resistive forces of 700 N backwards, so the resultant force is F=2500 N−700 N=1800 NF = 2500 \text{ N} - 700 \text{ N} = 1800 \text{ N}F=2500 N−700 N=1800 N forwards.
The car’s mass is 1000 kg and acceleration is unknown, so use a=Fma = \frac{F}{m}a=mF.
Substitute: a=1800 N1000 kg=1.8 m/s2a = \frac{1800 \text{ N}}{1000 \text{ kg}} = 1.8 \text{ m/s}^2a=1000 kg1800 N=1.8 m/s2. The car accelerates forwards at 1.8 m/s^2.
Using the wrong force
Do not put the engine thrust, pull or push into F=maF = maF=ma unless it is already the resultant force. If friction, drag or another opposing force is given, combine the forces first.
This part is Higher Tier only.
Inertial mass
Inertial mass is a measure of how difficult it is to change the velocity of an object. It is defined as the ratio of force over acceleration: m=Fam = \frac{F}{a}m=aF.
A larger inertial mass means the same resultant force produces a smaller acceleration. This is why a loaded van is harder to get moving than an empty van.
In exams, you may be asked to estimate speeds, accelerations and forces for everyday transport.
The symbol ∼\sim∼ means “approximately” or “of the order of”. For example, a typical car might have m∼1000 kgm \sim 1000 \text{ kg}m∼1000 kg.
Useful rough values:
Estimating a braking force
A 1200 kg car slows from 20 m/s to 0 m/s in 4.0 s, so a=0 m/s−20 m/s4.0 s=−5.0 m/s2a = \frac{0 \text{ m/s} - 20 \text{ m/s}}{4.0 \text{ s}} = -5.0 \text{ m/s}^2a=4.0 s0 m/s−20 m/s=−5.0 m/s2.
Use Newton’s Second Law: F=ma=1200 kg×−5.0 m/s2=−6000 NF = ma = 1200 \text{ kg} \times -5.0 \text{ m/s}^2 = -6000 \text{ N}F=ma=1200 kg×−5.0 m/s2=−6000 N.
The negative sign means the force acts opposite to the motion. As an estimate, the braking force is F∼6000 NF \sim 6000 \text{ N}F∼6000 N backwards.
You need to know how to investigate:
A common setup uses a dynamics trolley on a track, a string over a pulley, and a hanging mass. Light gates are sensors that time a card as it passes through them. A data logger records the timings and can calculate acceleration.

To test how force affects acceleration:
You should find that acceleration increases in direct proportion to resultant force.
To test how mass affects acceleration:
You should find that increasing mass decreases acceleration.
The expected graph shapes are shown below.

Changing two variables at once
When testing the effect of force, keep the total moving mass constant by moving masses between the trolley and the hanging holder. Do not simply add extra masses to the hanger.
In the exam
Find the resultant force before using F=maF = maF=ma.
Check units: force in N, mass in kg, acceleration in m/s^2.
For estimates, use rounded values and the symbol ∼\sim∼ when your answer is approximate.
In practical questions, state what is changed, what is kept constant, and how acceleration is measured.
Check yourself
Test yourself on this topic, or move on to the next guide.
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