- How forces can make objects rotate about a pivot.
- How to calculate a moment using M=FdM=FdM=Fd.
- How to use the balancing rule for clockwise and anticlockwise moments.
- How simple levers and gears transmit turning effects.
This is part of the separate GCSE Physics content, so it is worth learning carefully if you study GCSE Physics.
You already know that a force is a push or pull. A force can change the speed, shape, or direction of motion of an object.
Sometimes, instead of just moving an object in a straight line, a force makes it rotate. For example:
- pushing a door open about its hinge
- using a spanner to turn a nut
- pressing down on one side of a seesaw
- turning bicycle pedals
A pivot is the point about which an object turns. A door turns about its hinges, and a seesaw turns about its central support.
Pivot
A pivot is the fixed point or axis about which an object rotates.
If you push directly at the pivot, the object usually will not turn much. The further away from the pivot you apply the force, the larger the turning effect.
The moment of a force is the turning effect of that force about a pivot.
Moment of a force
The moment of a force is its turning effect about a pivot. A larger moment means a stronger tendency to rotate.
A moment can be clockwise or anticlockwise, depending on which way the force tends to turn the object.
For example, pushing down on the right side of a seesaw gives a clockwise moment about the pivot. Pushing down on the left side gives an anticlockwise moment.
The distance in the moments equation is not just any distance. It must be the perpendicular distance from the pivot to the line of action of the force.
The line of action is an imaginary straight line in the direction the force acts.

Perpendicular distance
The perpendicular distance is the shortest distance from the pivot to the line of action of the force, measured at right angles to that line.
Using the wrong distance
Do not automatically use the length of the object. In the equation, ddd is the perpendicular distance from the pivot to the force’s line of action.
The size of the moment is found using:
M=FdM = FdM=Fd
where:
- MMM is the moment of the force, measured in newton-metres, Nm
- FFF is the force, measured in newtons, N
- ddd is the perpendicular distance from the pivot to the line of action of the force, measured in metres, m
Bigger force or bigger distance means bigger moment
For the same pivot, increasing the force or applying the force further from the pivot increases the moment.
Calculating a moment
A 15 N force is applied at right angles to a door, 0.80 m from the hinge. Calculate the moment about the hinge.
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The hinge is the pivot, and the force acts at right angles to the door, so the perpendicular distance is d=0.80 md=0.80\ \text{m}d=0.80 m.
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Use M=FdM=FdM=Fd and substitute the values:
M=15 N×0.80 mM = 15\ \text{N} \times 0.80\ \text{m}M=15 N×0.80 m
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Calculate the moment:
M=12 NmM = 12\ \text{Nm}M=12 Nm
So the moment about the hinge is 12 Nm.
Quick sense check
If either the force or the distance doubles, the moment doubles. This is a useful way to spot answers that are much too big or too small.
An object is balanced if it has no overall turning effect about the pivot. This means it will not start rotating.
For a balanced object:
total clockwise moment=total anticlockwise moment\text{total clockwise moment} = \text{total anticlockwise moment}total clockwise moment=total anticlockwise moment
This is very common in questions about seesaws, beams, rulers, and levers.
The balancing rule
If an object is balanced, the total clockwise moment about the pivot equals the total anticlockwise moment about the pivot.
When more than one force acts, calculate each moment separately. Then add the clockwise moments together and add the anticlockwise moments together.
You may need to find a missing force or distance.
From:
M=FdM = FdM=Fd
you can rearrange to:
F=MdF = \frac{M}{d}F=dM
or:
d=MFd = \frac{M}{F}d=FM
Finding a missing force on a balanced beam
A beam is balanced on a pivot. A 6 N force acts downward 0.40 m to the left of the pivot. A second force acts downward 0.30 m to the right of the pivot. Calculate the size of the second force.
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The left-hand force produces one moment:
M=6 N×0.40 m=2.4 NmM = 6\ \text{N} \times 0.40\ \text{m} = 2.4\ \text{Nm}M=6 N×0.40 m=2.4 Nm
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The beam is balanced, so the moment on the right must also be 2.4 Nm.
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Use F=MdF=\frac{M}{d}F=dM for the right-hand force:
F=2.4 Nm0.30 m=8 NF = \frac{2.4\ \text{Nm}}{0.30\ \text{m}} = 8\ \text{N}F=0.30 m2.4 Nm=8 N
So the second force is 8 N.
Forgetting to compare directions
Moments only balance if clockwise moments equal anticlockwise moments. Do not just add all the forces or all the distances together.
A lever is a rigid object that turns about a pivot. Levers are used to transmit the rotational effect of a force.
Examples include:
- a crowbar
- scissors
- a bottle opener
- a spanner
- a seesaw
A lever can make a job easier by allowing a smaller force to produce a larger moment. This usually happens when the force is applied far from the pivot.
Lever
A lever is a rigid object that rotates about a pivot to transmit the turning effect of a force.
A long-handled spanner is easier to use than a short-handled spanner because the force is applied further from the pivot. For the same force, the moment is larger.
Using a lever to increase force
A crowbar is used to lift a heavy object. A person pushes down with 40 N at a distance of 0.75 m from the pivot. The heavy object is 0.15 m from the pivot. Estimate the upward force on the heavy object, assuming the lever is balanced.
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Calculate the input moment from the person’s push:
M=40 N×0.75 m=30 NmM = 40\ \text{N} \times 0.75\ \text{m} = 30\ \text{Nm}M=40 N×0.75 m=30 Nm
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For balance, the moment lifting the heavy object must also be 30 Nm.
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Use F=MdF=\frac{M}{d}F=dM for the force on the heavy object:
F=30 Nm0.15 m=200 NF = \frac{30\ \text{Nm}}{0.15\ \text{m}} = 200\ \text{N}F=0.15 m30 Nm=200 N
So the lever can produce an upward force of about 200 N on the object.
Levers do not create energy
A lever can increase the force, but the end where you apply the force usually moves a greater distance. The machine makes the force more useful, not magical.
A gear is a wheel with teeth around its edge. Gears work by meshing their teeth together, so one rotating gear forces another gear to rotate.
Gear
A gear is a toothed wheel that transmits rotation and turning effects to another gear.
The gear you turn or drive is called the input gear. The gear being driven is called the output gear.
When two gears mesh:
- they turn in opposite directions
- the teeth transmit forces between the gears
- those forces create moments about the gears’ axles
- different-sized gears can change the speed and turning effect of the rotation
You may also see the word torque. At GCSE, you can think of torque as the turning effect of a force, very similar to moment.

If a large gear drives a smaller gear, the smaller gear turns faster. However, the smaller gear has a smaller turning effect.
If a small gear drives a larger gear, the larger gear turns more slowly. However, the larger gear has a greater turning effect.
This is why low gears on a bike help you climb hills: they give a larger turning effect at the wheel, even though the wheel turns more slowly for each pedal rotation.
Explaining a simple gear system
A large input gear turns clockwise and drives a smaller output gear. Explain what happens to the output gear.
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Because the gears are meshed, the output gear must rotate in the opposite direction, so it turns anticlockwise.
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The output gear is smaller, so it turns faster than the larger input gear.
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The faster output rotation comes with a smaller turning effect, so this gear arrangement increases speed but reduces the moment available at the output.
Same direction gears
Two gears touching directly do not turn in the same direction. Meshed gears always rotate in opposite directions.
Moments, levers, and gears are all about turning effects.
A force can cause rotation if it acts at a distance from a pivot. The moment depends on both the size of the force and the perpendicular distance from the pivot. Levers use this idea with a rigid bar, and gears use forces between teeth to pass rotation from one axle to another.
In the exam
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Identify the pivot first, then decide which forces produce clockwise and anticlockwise moments.
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Use the perpendicular distance from the pivot to the force’s line of action, not just the length of the object.
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For balanced objects, set total clockwise moment equal to total anticlockwise moment, then rearrange M=FdM=FdM=Fd carefully.
Check yourself
- Why does pushing a door near the handle produce a larger moment than pushing near the hinge?
- A force of 20 N acts 0.50 m from a pivot. What is the moment?
- If a large gear drives a smaller gear, what happens to the direction, speed, and turning effect of the smaller gear?