Revision notes for AQA GCSE Physics Pressure in a fluid. Open the guide for explanations and worked examples. Written against the AQA GCSE Physics (8463) specification, so the content matches what's examinable rather than general Physics background.
Revision notes for AQA GCSE Physics Pressure in a fluid. Open the guide for explanations and worked examples. Written against the AQA GCSE Physics (8463) specification, so the content matches what's examinable rather than general Physics background.
Pressure tells you how concentrated a force is. The same force can make a large pressure if it acts over a small area, or a smaller pressure if it is spread over a larger area.
A force that acts normal to a surface acts at right angles to that surface.
Pressure
Pressure is the force acting normally on each square metre of a surface. It is calculated using:
p=FAp = \frac{F}{A}p=AFwhere ppp is pressure in pascals (Pa), FFF is force in newtons (N), and AAA is area in square metres (m²).
One pascal is one newton per square metre.
Area units matter
If the area is given in cm², convert it to m² before using the equation. A common conversion is: 10 000 cm² = 1 m².
Calculating pressure from force and area
A student presses down on the floor with a force of 600 N. The area of their shoe in contact with the floor is 0.030 m². Calculate the pressure on the floor.
Choose the pressure equation because you know force and area:
p=FAp = \frac{F}{A}p=AFSubstitute the values with units:
p=600 N0.030 m2p = \frac{600 \ \text{N}}{0.030 \ \text{m}^2}p=0.030 m2600 NCalculate the pressure:
p=20 000 Pap = 20\,000 \ \text{Pa}p=20000 PaSo the pressure on the floor is 20 000 Pa.
A fluid is any substance that can flow. That means both liquids and gases are fluids.
Fluid
A fluid is a liquid or a gas. Fluids can flow and take the shape of their container.
Fluids exert pressure on surfaces. In a stationary fluid, pressure at a point acts equally in all directions. However, the force caused by that pressure on a surface acts normal to the surface.
For example, water in a tank pushes sideways on the walls, downwards on the base, and upwards on anything submerged in it.
Fluid pressure causes normal forces
Pressure in a fluid causes a force at right angles to any surface it touches.
Pressure vs force
Pressure is not usually drawn as one single arrow in one direction. The force caused by pressure is what acts at right angles to a surface.
In a liquid, pressure increases as you go deeper. This is because a deeper point has a taller column of liquid above it. That column has weight, so it presses down more.
The diagram shows that pressure is greater at point B than at point A because B is deeper below the liquid surface.

Density
Density, ρ\rhoρ, is mass per unit volume. A denser liquid has more mass packed into each cubic metre, so it produces a larger pressure at the same depth.
The other factor is gravitational field strength, ggg. This tells you the force of gravity on each kilogram of mass. On Earth it is usually about 9.8 N/kg, but in GCSE questions you may be told to use 10 N/kg.
The pressure difference due to a column of liquid is:
p=hρgp = h \rho gp=hρgwhere:
What affects liquid pressure
Liquid pressure increases if the depth increases, the density of the liquid increases, or the gravitational field strength increases.
You can understand p=hρgp = h\rho gp=hρg from earlier ideas:
So the equation is really a combination of density, weight and pressure.
Using the wrong height
In p=hρgp = h\rho gp=hρg, hhh is the vertical depth below the surface, or the vertical height difference between two points. It is not the length of a sloping pipe or the width of the container.
Calculating pressure difference between two depths
A diver moves from 0.40 m below the surface to 2.20 m below the surface. The density of water is 1000 kg/m³ and g=10 N/kgg = 10 \ \text{N/kg}g=10 N/kg. Calculate the increase in water pressure.
Find the vertical height difference:
h=2.20 m−0.40 m=1.80 mh = 2.20 \ \text{m} - 0.40 \ \text{m} = 1.80 \ \text{m}h=2.20 m−0.40 m=1.80 mSubstitute into the liquid pressure equation:
p=hρg=1.80×1000×10p = h\rho g = 1.80 \times 1000 \times 10p=hρg=1.80×1000×10Calculate the pressure difference:
p=18 000 Pap = 18\,000 \ \text{Pa}p=18000 PaThe water pressure has increased by 18 000 Pa.
Pressure difference, not always total pressure
The equation p=hρgp = h\rho gp=hρg gives the extra pressure due to the liquid column. If a question asks for total pressure below an open surface, add atmospheric pressure if it is supplied.
In the same liquid, points at the same vertical depth have the same pressure. This is true even if the container is wide, narrow or oddly shaped.
This is why the bottom of a dam has to be especially strong: the water pressure is greatest at the greatest depth.
Only vertical depth matters
For a stationary liquid, pressure depends on vertical depth, not on the total amount of liquid or the shape of the container.
An object in a fluid has pressure acting on all its surfaces.
The sides of the object are usually at similar depths, so the sideways pressure forces balance. But the bottom of the object is deeper than the top, so the pressure on the bottom is larger than the pressure on the top.
This creates a resultant upward force called upthrust.

Upthrust
Upthrust is the resultant upward force on an object in a fluid, caused by the fluid pressure being greater on the bottom surface than on the top surface.
Where upthrust comes from
Upthrust is not a separate “mystery force”. It is the result of pressure forces, with the upward force on the bottom being larger than the downward force on the top.
A submerged or floating object has two important vertical forces:
An object floats when the upthrust equals its weight. The resultant force is then zero, so the object stays at rest or moves at constant speed.
An object sinks if its weight is greater than the maximum upthrust the fluid can provide.
Upthrust depends on the fluid displaced. Displaced fluid means fluid pushed out of the way by the object. A larger displaced volume or a denser fluid gives a larger upthrust.
Floating is not force-free
A floating object still has forces acting on it. Its weight and upthrust are equal in size and opposite in direction, so the resultant force is zero.
Deciding whether an object sinks
A small object has a weight of 5.0 N. When it is fully submerged in water, the upthrust on it is 3.5 N. Decide whether it floats or sinks.
Compare the downward force and upward force: weight is 5.0 N downwards, upthrust is 3.5 N upwards.
Calculate the resultant force:
5.0 N−3.5 N=1.5 N5.0 \ \text{N} - 3.5 \ \text{N} = 1.5 \ \text{N}5.0 N−3.5 N=1.5 NThe resultant force is 1.5 N downwards, so the object sinks.
In the exam
Decide which pressure equation fits the information: use p=FAp = \frac{F}{A}p=AF for force and area, and p=hρgp = h\rho gp=hρg for liquid depth.
Check units carefully: area in m², depth in m, density in kg/m³, and pressure in Pa.
For liquid pressure, use the vertical depth or vertical height difference, not the length along a slope.
For floating and sinking, compare weight downwards with upthrust upwards.
Check yourself
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