Using xn+1=2xn2\displaystyle x_{n+1} = \frac{2}{x_n^2}xn+1=xn22 with x0=1x_0 = 1x0=1, find the values of x1x_1x1, x2 x_2\,x2 and x3x_3x3.
124 exam-style questions on OCR GCSE Maths Iteration. Each one has a worked solution and a mark scheme showing where the marks go.