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Changing the Subject of a Formula

Changing the Subject of a Formula

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Question 147

Verify that x=−6y−125\displaystyle x = \frac{-6y - 12}{5}x=5−6y−12​ is the subject of 5x+6y+12=05x + 6y + 12 = 05x+6y+12=0

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Changing the Subject of a Formula Questions

  1. GCSE
  2. /Maths
  3. /Changing the Subject of a Formula

210 exam-style questions on OCR GCSE Maths Changing the Subject of a Formula. Each one has a worked solution and a mark scheme showing where the marks go.

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