- How to read the gradient and y-intercept of a straight line.
- How to use the form y=mx+cy = mx + cy=mx+c.
- How to find an equation from a graph or from key information.
- How to recognise parallel and horizontal lines.
A coordinate grid has an xxx-axis going across and a yyy-axis going up. Points are written as pairs, like (3, 4).

Coordinate pair
A coordinate pair tells you the xxx-coordinate first, then the yyy-coordinate. So (3, 4) means 3 across and 4 up.
A line crosses the yyy-axis when its xxx-coordinate is 0. This is a very common one-mark question.
Crossing the y-axis
- The line is y=4x−6y = 4x - 6y=4x−6. A line crosses the yyy-axis where x=0x = 0x=0.

-
Substitute x=0x = 0x=0 into the equation:
y=4(0)−6=−6y = 4(0) - 6 = -6y=4(0)−6=−6
-
The value of yyy where the line crosses the yyy-axis is -6.
Gradient
The gradient of a straight line tells you its steepness. It is the change in yyy divided by the change in xxx, written as m=change in ychange in xm = \frac{\text{change in } y}{\text{change in } x}m=change in xchange in y.
A positive gradient goes up as you move from left to right. A negative gradient goes down.

Finding a gradient from two points
- Choose two clear points on the line, such as (1, 7) and (3, 1).

-
From the first point to the second, xxx increases by 2 and yyy decreases by 6.
-
Work out the gradient:
m=−62=−3m = \frac{-6}{2} = -3m=2−6=−3
-
The gradient is -3, so the line slopes downwards from left to right.
Direction check
Always read gradients from left to right. Up means positive gradient; down means negative gradient.
The most useful straight-line form at GCSE is:
y=mx+cy = mx + cy=mx+c
y-intercept
The y-intercept is where a line crosses the yyy-axis. In y=mx+cy = mx + cy=mx+c, the value of ccc is the yyy-intercept, so the crossing point is (0,c)(0, c)(0,c).
What m and c mean
In y=mx+cy = mx + cy=mx+c, mmm is the gradient and ccc is the value where the line crosses the yyy-axis.

Reading y=6−2x
-
Rewrite the equation in the usual order:
y=−2x+6y = -2x + 6y=−2x+6
-
The number multiplying xxx is -2, so the gradient is -2.
-
The number on its own is 6, so the line crosses the yyy-axis at (0, 6).
Forgetting the hidden 1
In y=2−xy = 2 - xy=2−x, the xxx term is really −1x-1x−1x, so the gradient is -1, not 2 or 1.
If you know the gradient and where the line crosses the yyy-axis, you can put them straight into y=mx+cy = mx + cy=mx+c.
Using a gradient and a y-intercept
-
The line has gradient 4, so m=4m = 4m=4.
-
It passes through (0, -3), so it crosses the yyy-axis at -3. This means c=−3c = -3c=−3.
-
Substitute into y=mx+cy = mx + cy=mx+c:
y=4x−3y = 4x - 3y=4x−3
To find a line’s equation from a graph, you need two things:
- the gradient
- the y-intercept
If the graph clearly crosses the yyy-axis, read that point first.
Finding an equation from two graph points
- The line goes through (0, 5) and (2, -1). Since (0, 5) is on the yyy-axis, c=5c = 5c=5.

-
From (0, 5) to (2, -1), xxx increases by 2 and yyy decreases by 6.
-
Work out the gradient:
m=−62=−3m = \frac{-6}{2} = -3m=2−6=−3
-
Put m=−3m = -3m=−3 and c=5c = 5c=5 into y=mx+cy = mx + cy=mx+c:
y=−3x+5y = -3x + 5y=−3x+5
Sometimes the equation is not already in the form y=mx+cy = mx + cy=mx+c. The subject of an equation is the variable on its own. So “make yyy the subject” means rearrange until it starts with y=y =y=.
Finding the gradient after rearranging
-
Start with 3y−6x=123y - 6x = 123y−6x=12. Add 6x6x6x to both sides:
3y−6x=123y=6x+12\begin{aligned}
3y - 6x &= 12 \\
3y &= 6x + 12
\end{aligned}3y−6x3y=12=6x+12
-
Divide every term by 3:
y=2x+4y = 2x + 4y=2x+4
-
Now compare with y=mx+cy = mx + cy=mx+c. The gradient is 2.
Parallel lines
Parallel lines are lines that stay the same distance apart and never meet. Straight parallel lines have the same gradient.

So if two lines are parallel, keep the same mmm value. The ccc value can change.
Finding a parallel line
-
Rearrange x+2y=10x + 2y = 10x+2y=10 into y=mx+cy = mx + cy=mx+c:
x+2y=102y=10−xy=−12x+5\begin{aligned}
x + 2y &= 10 \\
2y &= 10 - x \\
y &= -\frac{1}{2}x + 5
\end{aligned}x+2y2yy=10=10−x=−21x+5
-
The gradient is −12-\frac{1}{2}−21, so a parallel line must also have gradient −12-\frac{1}{2}−21.
-
The new line passes through (0, 1), so its y-intercept is 1.
-
The equation is y=−12x+1y = -\frac{1}{2}x + 1y=−21x+1.
When matching lines to equations, look for quick clues:
- Does it go up or down?
- Where does it cross the yyy-axis?
- Is it horizontal?
A horizontal line is flat. Its equation looks like y=cy = cy=c, because the yyy-value stays the same.

Matching lines to equations
-
A positive line through the origin matches y=2xy = 2xy=2x, because there is no added constant.
-
A flat line crossing the yyy-axis at 4 matches y=4y = 4y=4.
-
A positive line crossing the yyy-axis at 4 matches y=2x+4y = 2x + 4y=2x+4.
-
A negative line crossing the yyy-axis at 4 matches y=4−2xy = 4 - 2xy=4−2x.
In the exam
-
Put the equation into y=mx+cy = mx + cy=mx+c before reading the gradient.
-
On a graph, choose two exact grid points and use change in yyy over change in xxx.
-
For parallel lines, keep the gradient the same and change the intercept if needed.
Check yourself
- Can you read the gradient and y-intercept from y=7−4xy = 7 - 4xy=7−4x?
- If a line goes through (0, -6) and has gradient 3, what would its equation look like?
- Why do parallel lines have the same mmm value in y=mx+cy = mx + cy=mx+c?