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5.1 Monitoring chemical reactions

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Question 57
H

A student dissolves a sample of sodium carbonate in water and makes the solution up to 250 cm3\mathrm{cm^{3}}cm3.

25.0 cm3\mathrm{cm^{3}}cm3 of this solution is exactly neutralised by 17.00 cm3\mathrm{cm^{3}}cm3 of 0.100 mol/dm3\mathrm{mol/dm^{3}}mol/dm3 hydrochloric acid.

Na2CO3+2HCl→2NaCl+H2O+CO2 \mathrm{Na_{2}CO_{3} + 2HCl \rightarrow 2NaCl + H_{2}O + CO_{2}} Na2​CO3​+2HCl→2NaCl+H2​O+CO2​

Relative formula mass (MrM_rMr​): Na2CO3\mathrm{Na_{2}CO_{3}}Na2​CO3​ = 106.0

What was the mass of the sample of sodium carbonate?

[1]
A

0.0901 g

B

0.180 g

C

0.901 g

D

1.80 g

Markscheme

5.1 Monitoring chemical reactions Questions

  1. GCSE
  2. /Chemistry
  3. /5.1 Monitoring chemical reactions

152 exam-style questions on OCR GCSE Chemistry 5.1 Monitoring chemical reactions, covering 5.1.1 The technique of titration, 5.1.2 Theoretical mass, percentage yield and atom economy, 5.1.3 Concentration of a solution in mol/dm3, 5.1.4 Concentration calculations and titration results, 5.1.5 Molar gas volume and volumes of gases in reactions, and 5.1.6 Choosing a reaction pathway. Each one has a worked solution and a mark scheme showing where the marks go.

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