A computer models this reversible reaction in a closed system.
R⇌S \mathrm{R \rightleftharpoons S} R⇌SThe temperature is constant. The model contains 320 particles of R and 280 particles of S, and these amounts are no longer changing.
During the next 10 seconds, the computer records 24 particles changing from R to S and 24 particles changing from S to R.
What does this show?
The forward and reverse reactions continue at the same rate.
The reaction rates are different because the amounts of R and S are different.
The equilibrium lies to the right because 24 particles of S are formed.
The amounts of R and S must become equal because 24 particles change each way.
124 exam-style questions on OCR GCSE Chemistry 5.3 Equilibria, covering 5.3.1 Reversible reactions and dynamic equilibrium and 5.3.2 Changing the position of equilibrium. Each one has a worked solution and a mark scheme showing where the marks go.