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5.3 Equilibria

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Question 4
H

Chlorine can be made by reacting hydrogen chloride gas with oxygen.

4HCl(g)+O2(g)⇌2Cl2(g)+2H2O(g) \mathrm{4HCl(g) + O_{2}(g) \rightleftharpoons 2Cl_{2}(g) + 2H_{2}O(g)} 4HCl(g)+O2​(g)⇌2Cl2​(g)+2H2​O(g)

The forward reaction is exothermic.

The table shows the percentage of hydrogen chloride converted to chlorine at equilibrium under different conditions.

Temperature (°C)Hydrogen chloride converted at 1 atm (%)Hydrogen chloride converted at 5 atm (%)
2509295
3508489
4507380
5506170
a.

Which conditions in the table give the highest percentage of hydrogen chloride converted?

[1]
b.

Explain the effects of temperature and pressure shown in the table.

Suggest two other ways to increase the amount of chlorine in the equilibrium mixture, and explain whether adding a catalyst would increase the percentage of hydrogen chloride converted.

[6]
c.

The company runs the process at about 400 °C, not 250 °C.

Suggest why.

[2]
Markscheme

5.3 Equilibria Questions

  1. GCSE
  2. /Chemistry
  3. /5.3 Equilibria

47 exam-style questions on OCR GCSE Chemistry 5.3 Equilibria, covering 5.3.1 Reversible reactions and dynamic equilibrium and 5.3.2 Changing the position of equilibrium. Each one has a worked solution and a mark scheme showing where the marks go.

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