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States of matter

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Question 29

Propane burns in oxygen at a temperature of 140∘C140^\circ\text{C}140∘C to form carbon dioxide and water.

The boiling points of propane and water are shown in the table below.

SubstanceBoiling point in ∘C^\circ\text{C}∘C
Propane-42
Water100

Use this information to add the missing state symbols to the equation for the reaction taking place.

C3H8(……… )+5O2(g)→3CO2(g)+4H2O(……… ) \text{C}_3\text{H}_8(\dots\dots\dots) + 5\text{O}_2(\text{g}) \rightarrow 3\text{CO}_2(\text{g}) + 4\text{H}_2\text{O}(\dots\dots\dots) C3​H8​(………)+5O2​(g)→3CO2​(g)+4H2​O(………)
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States of matter Questions

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