Skip to content

Course home

6.2 Quantitative analysis

6.2 Quantitative analysis

EasyMediumHard
1234567891011121314151617181920212223242526272829303132333435363738394041424344454647484950515253545556
Question 43

In a titration, 20.0 cm3 of a potassium hydroxide solution, KOH\text{KOH}KOH, is neutralised by a 0.150 mol dm-3 solution of sulfuric acid, H2SO4\text{H}_2\text{SO}_4H2​SO4​.

2KOH+H2SO4→K2SO4+2H2O 2\text{KOH} + \text{H}_2\text{SO}_4 \rightarrow \text{K}_2\text{SO}_4 + 2\text{H}_2\text{O} 2KOH+H2​SO4​→K2​SO4​+2H2​O

During the titration, 18.40 cm3 of sulfuric acid are required to completely neutralise the 20.0 cm3 of potassium hydroxide solution.

Calculate the concentration of the potassium hydroxide solution in mol dm−3\text{mol dm}^{-3}mol dm−3.

[4]
Markscheme

6.2 Quantitative analysis Questions

  1. GCSE
  2. /Chemistry
  3. /6.2 Quantitative analysis

119 exam-style questions on Edexcel GCSE Chemistry 6.2 Quantitative analysis, covering 6.2.1 Concentration in mol dm⁻³ and titration calculations, 6.2.2 Percentage yield and why actual yield falls short, 6.2.3 Atom economy of a reaction, 6.2.4 Choosing a reaction pathway, and 6.2.5 Molar volume of gases and Avogadro's law. Each one has a worked solution and a mark scheme showing where the marks go.

Question bank