Potassium hydroxide solution reacts with dilute nitric acid:
KOH(aq)+HNO3(aq)→KNO3(aq)+H2O(l) \text{KOH(aq)} + \text{HNO}_3\text{(aq)} \rightarrow \text{KNO}_3\text{(aq)} + \text{H}_2\text{O(l)} KOH(aq)+HNO3(aq)→KNO3(aq)+H2O(l)30.0 cm3 of 0.150 mol dm-3 potassium hydroxide, KOH\text{KOH}KOH, solution is added to 40.0 cm3 of 0.120 mol dm-3 dilute nitric acid, HNO3\text{HNO}_3HNO3.
Determine which reagent is in excess. Show your working.
157 exam-style questions on Edexcel GCSE Chemistry 6.2 Quantitative analysis, covering 6.2.1 Concentration in mol dm⁻³ and titration calculations, 6.2.2 Percentage yield and why actual yield falls short, 6.2.3 Atom economy of a reaction, 6.2.4 Choosing a reaction pathway, and 6.2.5 Molar volume of gases and Avogadro's law. Each one has a worked solution and a mark scheme showing where the marks go.