Skip to content

Course home

6.2 Quantitative analysis

6.2 Quantitative analysis

EasyMediumHard
1234567891011121314151617181920212223242526272829303132333435363738394041424344454647484950515253545556575859606162636465
Question 10

Propane-1,2-diol, C3H8O2\text{C}_3\text{H}_8\text{O}_2C3​H8​O2​, can be manufactured using two different commercial pathways.

  • Method A: Hydrolysis of propylene oxide
C3H6O+H2O→C3H8O2 \text{C}_3\text{H}_6\text{O} + \text{H}_2\text{O} \rightarrow \text{C}_3\text{H}_8\text{O}_2 C3​H6​O+H2​O→C3​H8​O2​ atom economy=100% \text{atom economy} = 100\% atom economy=100%
  • Method B: Reaction of 1-chloropropan-2-ol with sodium hydroxide
CH3CH(OH)CH2Cl+NaOH→CH3CH(OH)CH2OH+NaCl \text{CH}_3\text{CH(OH)CH}_2\text{Cl} + \text{NaOH} \rightarrow \text{CH}_3\text{CH(OH)CH}_2\text{OH} + \text{NaCl} CH3​CH(OH)CH2​Cl+NaOH→CH3​CH(OH)CH2​OH+NaCl atom economy=56.5% \text{atom economy} = 56.5\% atom economy=56.5%

Explain why Method A has an atom economy of 100%.

[1]
Markscheme

6.2 Quantitative analysis Questions

  1. GCSE
  2. /Chemistry
  3. /6.2 Quantitative analysis

157 exam-style questions on Edexcel GCSE Chemistry 6.2 Quantitative analysis, covering 6.2.1 Concentration in mol dm⁻³ and titration calculations, 6.2.2 Percentage yield and why actual yield falls short, 6.2.3 Atom economy of a reaction, 6.2.4 Choosing a reaction pathway, and 6.2.5 Molar volume of gases and Avogadro's law. Each one has a worked solution and a mark scheme showing where the marks go.

Question bank