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6.2 Quantitative analysis

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Question 21

Oxygen can be made by heating potassium chlorate.

2KClO3(s)→2KCl(s)+3O2(g)\mathrm{2KClO_3(s) \rightarrow 2KCl(s) + 3O_2(g)}2KClO3​(s)→2KCl(s)+3O2​(g)

Oxygen is the desired product.

Relative formula masses: KCl=74.5\mathrm{KCl} = 74.5KCl=74.5 and O2=32\mathrm{O_2} = 32O2​=32.

Calculate, to three significant figures, the atom economy of this method for producing oxygen.

Use the equation:

atom economy=total relative formula mass of desired producttotal relative formula mass of all products×100\text{atom economy} = \dfrac{\text{total relative formula mass of desired product}}{\text{total relative formula mass of all products}} \times 100atom economy=total relative formula mass of all productstotal relative formula mass of desired product​×100

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Markscheme

6.2 Quantitative analysis Questions

  1. GCSE
  2. /Chemistry
  3. /6.2 Quantitative analysis

151 exam-style questions on Edexcel GCSE Chemistry 6.2 Quantitative analysis, covering 6.2.1 Concentration in mol dm⁻³ and titration calculations, 6.2.2 Percentage yield and why actual yield falls short, 6.2.3 Atom economy of a reaction, 6.2.4 Choosing a reaction pathway, and 6.2.5 Molar volume of gases and Avogadro's law. Each one has a worked solution and a mark scheme showing where the marks go.

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