The equation for the reaction between sodium hydroxide solution and dilute nitric acid is:
NaOH+HNO3→NaNO3+H2O \text{NaOH} + \text{HNO}_3 \rightarrow \text{NaNO}_3 + \text{H}_2\text{O} NaOH+HNO3→NaNO3+H2OCalculate the atom economy for the production of sodium nitrate from sodium hydroxide and nitric acid.
(relative formula masses: NaOH=40.0\text{NaOH} = 40.0NaOH=40.0, HNO3=63.0\text{HNO}_3 = 63.0HNO3=63.0, NaNO3=85.0\text{NaNO}_3 = 85.0NaNO3=85.0, H2O=18.0\text{H}_2\text{O} = 18.0H2O=18.0)
Give your answer to one decimal place.
119 exam-style questions on Edexcel GCSE Chemistry 6.2 Quantitative analysis, covering 6.2.1 Concentration in mol dm⁻³ and titration calculations, 6.2.2 Percentage yield and why actual yield falls short, 6.2.3 Atom economy of a reaction, 6.2.4 Choosing a reaction pathway, and 6.2.5 Molar volume of gases and Avogadro's law. Each one has a worked solution and a mark scheme showing where the marks go.