A bottle in a school laboratory contains copper sulfate solution with a concentration of 24.0 g dm−324.0\,\mathrm{g\,dm^{-3}}24.0gdm−3. A student measures out 0.350 dm30.350\,\mathrm{dm^{3}}0.350dm3 of this solution into a beaker.
Calculate the mass of copper sulfate in the solution in the beaker.
Use the equation:
mass of solute (g)=concentration (g dm−3)×volume of solution (dm3)\text{mass of solute (g)}=\text{concentration }(\mathrm{g\,dm^{-3}})\times\text{volume of solution }(\mathrm{dm^{3}})mass of solute (g)=concentration (gdm−3)×volume of solution (dm3)
142 exam-style questions on Edexcel GCSE Chemistry 2.6 Calculations involving masses, covering 2.6.1 Relative formula mass and percentage composition, 2.6.2 Empirical and molecular formulae, 2.6.3 Conservation of mass, 2.6.4 Reacting masses and concentration in g dm⁻³, 2.6.5 The mole and the Avogadro constant, and 2.6.6 Limiting reactants and stoichiometry. Each one has a worked solution and a mark scheme showing where the marks go.