Hydrochloric acid containing 0.60 mol of HCl reacts completely with calcium carbonate. The equation for the reaction is CaCO3+2HCl→CaCl2+H2O+CO2\mathrm{CaCO_{3}} + 2\mathrm{HCl} \rightarrow \mathrm{CaCl_{2}} + \mathrm{H_{2}O} + \mathrm{CO_{2}}CaCO3+2HCl→CaCl2+H2O+CO2. What amount of calcium carbonate is used up?
0.20 mol
0.30 mol
0.60 mol
1.2 mol
142 exam-style questions on Edexcel GCSE Chemistry 2.6 Calculations involving masses, covering 2.6.1 Relative formula mass and percentage composition, 2.6.2 Empirical and molecular formulae, 2.6.3 Conservation of mass, 2.6.4 Reacting masses and concentration in g dm⁻³, 2.6.5 The mole and the Avogadro constant, and 2.6.6 Limiting reactants and stoichiometry. Each one has a worked solution and a mark scheme showing where the marks go.