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2.6 Calculations involving masses

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Question 20

A sealed tube contains a pure nitrogen oxide. Oxygen makes up 63.2% of its mass. Relative atomic masses: N=14\mathrm{N} = 14N=14, O=16\mathrm{O} = 16O=16.

Which formula does the nitrogen oxide have?

[1]
A

NO\mathrm{NO}NO

B

N2O3\mathrm{N_{2}O_{3}}N2​O3​

C

N2O\mathrm{N_{2}O}N2​O

D

N2O5\mathrm{N_{2}O_{5}}N2​O5​

Markscheme

2.6 Calculations involving masses Questions

  1. GCSE
  2. /Chemistry
  3. /2.6 Calculations involving masses

142 exam-style questions on Edexcel GCSE Chemistry 2.6 Calculations involving masses, covering 2.6.1 Relative formula mass and percentage composition, 2.6.2 Empirical and molecular formulae, 2.6.3 Conservation of mass, 2.6.4 Reacting masses and concentration in g dm⁻³, 2.6.5 The mole and the Avogadro constant, and 2.6.6 Limiting reactants and stoichiometry. Each one has a worked solution and a mark scheme showing where the marks go.

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