A 25.0 cm3\mathrm{cm^{3}}cm3 sample of vinegar was diluted with water to make 250 cm3\mathrm{cm^{3}}cm3 of solution. 25.0 cm3\mathrm{cm^{3}}cm3 of the diluted solution was neutralised by 18.75 cm3\mathrm{cm^{3}}cm3 of 0.100 mol dm−3\mathrm{mol\,dm^{-3}}moldm−3 sodium hydroxide solution.
CH3COOH+NaOH→CH3COONa+H2O\mathrm{CH_{3}COOH + NaOH \rightarrow CH_{3}COONa + H_{2}O}CH3COOH+NaOH→CH3COONa+H2O
What was the concentration of ethanoic acid in the original, undiluted vinegar? (Mr M_r\,Mr of ethanoic acid = 60)
4.50 g dm−3\mathrm{g\,dm^{-3}}gdm−3
22.5 g dm−3\mathrm{g\,dm^{-3}}gdm−3
45.0 g dm−3\mathrm{g\,dm^{-3}}gdm−3
80.0 g dm−3\mathrm{g\,dm^{-3}}gdm−3
43 exam-style questions on Edexcel GCSE Chemistry 10.4 Alcohols and carboxylic acids, covering 10.4.1 Alcohols and the -OH functional group, 10.4.2 Carboxylic acids and the -COOH functional group, 10.4.3 Oxidation of alcohols and homologous series, and 10.4.4 Fermentation and fractional distillation of ethanol. Each one has a worked solution and a mark scheme showing where the marks go.