Skip to content

Course home

3.3 Yield and atom economy of chemical reactions

3.3 Yield and atom economy of chemical reactions

EasyMedium
12345678910111213
Question 2

Titanium chloride reacts with magnesium to produce titanium. The equation for the reaction is:

TiCl4+2Mg→Ti+2MgCl2 \text{TiCl}_4 + 2\text{Mg} \rightarrow \text{Ti} + 2\text{MgCl}_2 TiCl4​+2Mg→Ti+2MgCl2​

Calculate the percentage atom economy for obtaining titanium from this reaction. Use the equation:

Percentage atom economy=Ar of TiMr of TiCl4+2×Ar of Mg×100 \text{Percentage atom economy} = \frac{A_{\text{r}}\text{ of Ti}}{M_{\text{r}}\text{ of TiCl}_4 + 2 \times A_{\text{r}}\text{ of Mg}} \times 100 Percentage atom economy=Mr​ of TiCl4​+2×Ar​ of MgAr​ of Ti​×100

Relative atomic masses (ArA_{\text{r}}Ar​): Mg=24\text{Mg} = 24Mg=24, Ti=48\text{Ti} = 48Ti=48. Relative formula mass (MrM_{\text{r}}Mr​): TiCl4=190\text{TiCl}_4 = 190TiCl4​=190.

[3]
Markscheme

3.3 Yield and atom economy of chemical reactions Questions

  1. GCSE
  2. /Chemistry
  3. /3.3 Yield and atom economy of chemical reactions

31 exam-style questions on AQA GCSE Chemistry 3.3 Yield and atom economy of chemical reactions, covering 3.3.1 Percentage yield and 3.3.2 Atom economy. Each one has a worked solution and a mark scheme showing where the marks go.

Question bank