3.3 Yield and atom economy of chemical reactions

Question 6

Copper is extracted from copper(I) sulfide by heating it in a stream of oxygen gas. The equation for the reaction is:

\text{Cu}_2\text{S} + \text{O}_2 \rightarrow 2\text{Cu} + \text{SO}_2

Calculate the percentage atom economy for obtaining copper from this reaction.

Use the equation:

\text{Percentage atom economy} = \frac{2 \times A_{\text{r}}\text{ of Cu}}{M_{\text{r}}\text{ of Cu}_2\text{S} + M_{\text{r}}\text{ of O}_2} \times 100

Relative atomic masses ( $ArA_{\text{r}}$ ): $Cu=63.5\text{Cu} = 63.5$ . Relative formula masses ( $MrM_{\text{r}}$ ): $Cu2S=159\text{Cu}_2\text{S} = 159$ , $O2=32\text{O}_2 = 32$ .

[3]

1 2 3 4 5 6 7 8 9 10 11 12 13

Copper is extracted from copper(I) sulfide by heating it in a stream of oxygen gas. The equation for the reaction is:

\text{Cu}_2\text{S} + \text{O}_2 \rightarrow 2\text{Cu} + \text{SO}_2

Calculate the percentage atom economy for obtaining copper from this reaction.

Use the equation:

\text{Percentage atom economy} = \frac{2 \times A_{\text{r}}\text{ of Cu}}{M_{\text{r}}\text{ of Cu}_2\text{S} + M_{\text{r}}\text{ of O}_2} \times 100

Relative atomic masses ( $ArA_{\text{r}}$ ): $Cu=63.5\text{Cu} = 63.5$ . Relative formula masses ( $MrM_{\text{r}}$ ): $Cu2S=159\text{Cu}_2\text{S} = 159$ , $O2=32\text{O}_2 = 32$ .

3.3 Yield and atom economy of chemical reactions

Question 6

Markscheme

3.3 Yield and atom economy of chemical reactions

Question 6

Markscheme

3.3 Yield and atom economy of chemical reactions

Question 6

3.3 Yield and atom economy of chemical reactions Questions

3.3 Yield and atom economy of chemical reactions

Question 6

3.3 Yield and atom economy of chemical reactions Questions