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The solvent does the dissolving, while the solute is distributed throughout it."},{"text":"A suspension forms when a solute dissolves in a solvent.","correct":false,"explanation":"A suspension contains undissolved particles that may settle, whereas dissolving produces a solution. The correct term is solution because the solute spreads evenly at particle level."},{"text":"A solute forms when a solute dissolves in a solvent.","correct":false,"explanation":"The solute is the substance being dissolved, not the mixture produced. The mixture formed when a solute dissolves in a solvent is called a solution."},{"text":"A solvent forms when a solute dissolves in a solvent.","correct":false,"explanation":"The solvent is the liquid that dissolves the solute, so it already exists before mixing. The resulting mixture is called a solution."}]},{"id":"a2e03bb5-d654-43cb-916a-d5e9ebeda736","cardType":"basic","points":1,"front":"What is the solute in a solution?","back":"The solute is the substance dissolved in a solvent.","mcqOptions":[{"text":"The solute is the substance dissolved in a solvent.","correct":true,"explanation":"The solute is the substance that dissolves. In a salt solution, for example, salt is the solute and water is the solvent."},{"text":"The solvent is the substance dissolved in a solvent.","correct":false,"explanation":"The solvent is the substance that does the dissolving, not usually the substance dissolved. The substance dissolved in a solvent is called the solute."},{"text":"The solution is the substance dissolved in a solvent.","correct":false,"explanation":"A solution is the complete mixture of solute and solvent. The individual substance dissolved in the solvent is the solute."},{"text":"The concentrate is the substance dissolved in a solvent.","correct":false,"explanation":"Concentrate describes a solution containing a relatively large amount of solute, not the dissolved substance itself. The correct term for that substance is solute."}]},{"id":"8b17740c-8b3b-4f7d-9db2-9b0a92789185","cardType":"basic","points":1,"front":"What does the concentration of a solution tell you?","back":"It tells you how much solute is present in a given volume of solution.","mcqOptions":[{"text":"It tells you how much solute is present in a given volume of solution.","correct":true,"explanation":"Concentration compares the amount of solute with the volume of the solution. A greater amount of solute in the same volume means a higher concentration."},{"text":"It tells you how much solvent is present in a given volume of solution.","correct":false,"explanation":"Concentration concerns the amount of dissolved solute, not the amount of solvent. The correct description measures solute present in a specified solution volume."},{"text":"It tells you how much solution is present in a given mass of solute.","correct":false,"explanation":"This reverses the quantities used to describe concentration. Concentration tells you how much solute is present per given volume of solution."},{"text":"It tells you how much water is present in a given volume of solution.","correct":false,"explanation":"Water may be the solvent, but concentration is not generally defined by the amount of water. It describes the amount of solute in a given solution volume."}]},{"id":"d0bbb8fe-6dbd-4934-90a1-d4adc6e8d568","cardType":"basic","points":1,"front":"What happens to concentration when more solute is added to the same volume?","back":"Adding more solute to the same volume makes the solution more concentrated.","mcqOptions":[{"text":"Adding more solute to the same volume makes the solution more concentrated.","correct":true,"explanation":"With volume unchanged, adding solute increases the amount of solute per unit volume. Therefore, the concentration increases and the solution becomes more concentrated."},{"text":"Adding more solute to the same volume makes the solution more dilute.","correct":false,"explanation":"More dilute means less solute per unit volume, which would result from adding solvent or increasing volume. Adding solute to the same volume makes the solution more concentrated."},{"text":"Adding more solute to the same volume makes the solution unchanged.","correct":false,"explanation":"The volume may stay unchanged, but the amount of solute increases. Since concentration depends on solute amount per volume, the solution becomes more concentrated."},{"text":"Adding more solute to the same volume makes the solution less concentrated.","correct":false,"explanation":"Adding solute cannot lower the amount of solute per unit volume when volume is fixed. It increases concentration, so the solution becomes more concentrated."}]},{"id":"4d56de33-6d14-4e71-93c4-e231b3e0cf2e","cardType":"basic","points":1,"front":"What happens when the same solute is spread through a larger volume?","back":"The same solute spread through a larger volume makes the solution more dilute.","mcqOptions":[{"text":"The same solute spread through a larger volume makes the solution more dilute.","correct":true,"explanation":"The solute amount stays constant while the solution volume increases. This reduces the amount of solute per unit volume, so the concentration decreases and the solution becomes more dilute."},{"text":"The same solute spread through a larger volume makes the solution more concentrated.","correct":false,"explanation":"Increasing volume without adding solute reduces the solute amount per unit volume. Therefore the concentration decreases, making the solution more dilute."},{"text":"The same solute spread through a larger volume makes the solution unchanged.","correct":false,"explanation":"Although the solute mass is unchanged, concentration also depends on volume. A larger volume lowers the solute per unit volume, so the solution becomes more dilute."},{"text":"The same solute spread through a larger volume makes the solution saturated.","correct":false,"explanation":"Saturation means no more solute can dissolve under stated conditions. Spreading the same solute through more solvent lowers concentration and makes the solution more dilute."}]},{"id":"f90fecd2-5b84-4658-9951-20dfc905ac49","cardType":"basic","points":1,"front":"What is mass concentration?","back":"Concentration is the mass of solute per unit volume of solution.","mcqOptions":[{"text":"Concentration is the mass of solute per unit volume of solution.","correct":true,"explanation":"Mass concentration measures how much solute mass is present in each unit of solution volume. It is commonly expressed in grams per cubic decimetre, g/dm³."},{"text":"Density is the mass of solute per unit volume of solution.","correct":false,"explanation":"Density is the mass of a substance or mixture per unit volume, whereas concentration specifically measures solute mass per solution volume. The correct term here is concentration."},{"text":"Concentration is the volume of solute per unit mass of solution.","correct":false,"explanation":"This swaps both the measured quantities and their positions. Mass concentration is the mass of solute divided by the volume of solution."},{"text":"Solubility is the mass of solute per unit volume of solution.","correct":false,"explanation":"Solubility is the maximum amount that can dissolve under particular conditions. The mass of solute per unit volume in a solution is its concentration."}]},{"id":"61db9e35-88db-4c0b-a886-6af5a4a78b37","cardType":"basic","points":2,"front":"How do you calculate concentration in $\\text{g}/\\text{dm}^3$?","back":"Use $c = \\dfrac{m}{V}$, where $m$ is mass in grams and $V$ is volume in $\\text{dm}^3$.","mcqOptions":[{"text":"Use $c = \\dfrac{m}{V}$, where $m$ is mass in grams and $V$ is volume in $\\text{dm}^3$.","correct":true,"explanation":"Mass concentration is calculated by dividing solute mass, $m$, in grams by solution volume, $V$, in dm³. The resulting unit is g/dm³."},{"text":"Use $c = m \\times V$, where $m$ is mass in grams and $V$ is volume in $\\text{dm}^3$.","correct":false,"explanation":"Multiplying mass by volume gives the wrong relationship and units. Concentration is mass divided by volume, so the correct equation is $c = \\dfrac{m}{V}$."},{"text":"Use $c = \\dfrac{V}{m}$, where $m$ is mass in grams and $V$ is volume in $\\text{dm}^3$.","correct":false,"explanation":"This reverses the fraction and calculates volume per gram rather than mass concentration. The correct equation divides mass by volume: $c = \\dfrac{m}{V}$."},{"text":"Use $c = \\dfrac{m}{V}$, where $m$ is mass in kilograms and $V$ is volume in $\\text{cm}^3$.","correct":false,"explanation":"The equation has the right structure, but these units do not give concentration in g/dm³. Use mass in grams and volume in dm³."}]},{"id":"32be7ed5-c31a-45ee-aadf-32b2efdc6f34","cardType":"basic","points":1,"front":"What is the concentration of $20\\ \\text{g}$ of salt in $0.5\\ \\text{dm}^3$ of solution?","back":"The concentration is $\\dfrac{20}{0.5} = 40\\ \\text{g}/\\text{dm}^3$.","mcqOptions":[{"text":"The concentration is $\\dfrac{20}{0.5} = 40\\ \\text{g}/\\text{dm}^3$.","correct":true,"explanation":"Using $c = \\dfrac{m}{V}$ gives $c = \\dfrac{20\\ \\text{g}}{0.5\\ \\text{dm}^3} = 40\\ \\text{g}/\\text{dm}^3$. The volume is already in dm³."},{"text":"The concentration is $20 \\times 0.5 = 10\\ \\text{g}/\\text{dm}^3$.","correct":false,"explanation":"Multiplying mass by volume instead of dividing produces 10, but concentration requires $c = \\dfrac{m}{V}$. Therefore the correct value is $40\\ \\text{g}/\\text{dm}^3$."},{"text":"The concentration is $\\dfrac{0.5}{20} = 0.025\\ \\text{g}/\\text{dm}^3$.","correct":false,"explanation":"This divides volume by mass, reversing the concentration formula. Dividing the 20 g mass by 0.5 dm³ gives the correct concentration of $40\\ \\text{g}/\\text{dm}^3$."},{"text":"The concentration is $\\dfrac{20}{0.5} = 400\\ \\text{g}/\\text{dm}^3$.","correct":false,"explanation":"The division is set up correctly, but the arithmetic is out by a factor of ten. Since 20 divided by 0.5 equals 40, the correct concentration is $40\\ \\text{g}/\\text{dm}^3$."}]},{"id":"5741098f-38bc-48ee-9b19-acc023c8a524","cardType":"basic","points":1,"front":"How do you convert a volume from $\\text{cm}^3$ to $\\text{dm}^3$?","back":"Divide the volume in $\\text{cm}^3$ by 1000.","mcqOptions":[{"text":"Divide the volume in $\\text{cm}^3$ by 1000.","correct":true,"explanation":"One dm³ contains 1000 cm³, so converting cm³ to dm³ requires division by 1000. For example, 250 cm³ becomes 0.25 dm³."},{"text":"Multiply the volume in $\\text{cm}^3$ by 1000.","correct":false,"explanation":"Multiplying by 1000 converts dm³ to cm³, the opposite direction. To convert cm³ into dm³, divide by 1000."},{"text":"Divide the volume in $\\text{cm}^3$ by 100.","correct":false,"explanation":"The factor 100 applies to some length or area conversions, but volume conversion from cm³ to dm³ uses 1000. Divide by 1000."},{"text":"Divide the volume in $\\text{cm}^3$ by 10.","correct":false,"explanation":"A decimetre is ten centimetres, but cubed volume units require $10^3 = 1000$. Therefore cm³ must be divided by 1000 to obtain dm³."}]},{"id":"9d35f621-3230-4c6f-af99-a0d1af2a819d","cardType":"basic","points":1,"front":"What is $250\\ \\text{cm}^3$ in $\\text{dm}^3$?","back":"$$250\\ \\text{cm}^3 = 0.25\\ \\text{dm}^3$.","mcqOptions":[{"text":"$$250\\ \\text{cm}^3 = 0.25\\ \\text{dm}^3$.","correct":true,"explanation":"Since 1 dm³ equals 1000 cm³, divide 250 by 1000. This gives $0.25\\ \\text{dm}^3$."},{"text":"$$250\\ \\text{cm}^3 = 2.5\\ \\text{dm}^3$.","correct":false,"explanation":"The decimal has been shifted only two places, as in an area conversion. Volume conversion requires division by 1000, giving $0.25\\ \\text{dm}^3$."},{"text":"$$250\\ \\text{cm}^3 = 25\\ \\text{dm}^3$.","correct":false,"explanation":"This treats the conversion as division by 10, confusing the linear relationship between units with cubic volume. Dividing by 1000 gives $0.25\\ \\text{dm}^3$."},{"text":"$$250\\ \\text{cm}^3 = 250000\\ \\text{dm}^3$.","correct":false,"explanation":"Multiplying by 1000 reverses the conversion direction and greatly increases the value. Converting cm³ to dm³ requires division by 1000, producing $0.25\\ \\text{dm}^3$."}]},{"id":"56e1809e-93e4-4267-ae94-53672564bfa2","cardType":"basic","points":1,"front":"What is the consequence of using a volume in $\\text{cm}^3$ directly in $c = \\dfrac{m}{V}$?","back":"Using $\\text{cm}^3$ directly makes the concentration 1000 times too small.","mcqOptions":[{"text":"Using $\\text{cm}^3$ directly makes the concentration 1000 times too small.","correct":true,"explanation":"A volume in cm³ is numerically 1000 times larger than the same volume in dm³. Using it directly in the denominator therefore makes the calculated concentration 1000 times too small."},{"text":"Using $\\text{cm}^3$ directly makes the concentration 1000 times too large.","correct":false,"explanation":"The numerical volume becomes 1000 times larger when expressed in cm³, and it is in the denominator. This makes the calculated concentration 1000 times too small, not too large."},{"text":"Using $\\text{cm}^3$ directly makes the concentration 100 times too small.","correct":false,"explanation":"A factor of 100 is associated with square-unit conversions, not cubic-unit conversions. Since $1\\ \\text{dm}^3 = 1000\\ \\text{cm}^3$, the result is 1000 times too small."},{"text":"Using $\\text{cm}^3$ directly makes the concentration unchanged.","correct":false,"explanation":"The numerical value of the volume changes by a factor of 1000 between cm³ and dm³. Because volume is the denominator, using cm³ directly changes the calculated concentration."}]},{"id":"8fee3c5c-dc9c-46b6-9678-5529c31ee5fd","cardType":"basic","points":1,"front":"How do you calculate the mass of solute?","back":"Use $m = c \\times V$.","mcqOptions":[{"text":"Use $m = c \\times V$.","correct":true,"explanation":"Starting with $c = \\dfrac{m}{V}$ and multiplying both sides by $V$ gives $m = c \\times V$. Concentration and volume must use compatible units."},{"text":"Use $m = \\dfrac{c}{V}$.","correct":false,"explanation":"Dividing concentration by volume does not rearrange $c = \\dfrac{m}{V}$ correctly. Multiplying concentration by volume gives the solute mass: $m = c \\times V$."},{"text":"Use $m = c + V$.","correct":false,"explanation":"Mass concentration and volume are not added to find mass. Rearranging the concentration equation shows that mass equals concentration multiplied by volume, $m = c \\times V$."},{"text":"Use $m = \\dfrac{V}{c}$.","correct":false,"explanation":"This reverses concentration and volume and gives the wrong units. From $c = \\dfrac{m}{V}$, the correct rearrangement is $m = c \\times V$."}]},{"id":"8737ede7-0b4d-483c-a1ec-cc2a8f651558","cardType":"basic","points":2,"front":"What mass of solute is in $250\\ \\text{cm}^3$ of a $40\\ \\text{g}/\\text{dm}^3$ solution?","back":"The mass is $40 \\times 0.25 = 10\\ \\text{g}$.","mcqOptions":[{"text":"The mass is $40 \\times 0.25 = 10\\ \\text{g}$.","correct":true,"explanation":"Convert 250 cm³ to 0.25 dm³, then use $m = cV$. Thus $m = 40\\ \\text{g}/\\text{dm}^3 \\times 0.25\\ \\text{dm}^3 = 10\\ \\text{g}$."},{"text":"The mass is $40 \\times 250 = 10000\\ \\text{g}$.","correct":false,"explanation":"This uses 250 as though it were dm³ instead of converting 250 cm³ to 0.25 dm³. Using compatible units gives $40 \\times 0.25 = 10\\ \\text{g}$."},{"text":"The mass is $40 \\div 0.25 = 160\\ \\text{g}$.","correct":false,"explanation":"Dividing concentration by volume reverses the mass equation. Mass is concentration multiplied by volume, so $40 \\times 0.25 = 10\\ \\text{g}$."},{"text":"The mass is $40 \\times 0.025 = 1\\ \\text{g}$.","correct":false,"explanation":"The conversion from 250 cm³ to dm³ has shifted the decimal one place too far. It equals 0.25 dm³, so the mass is $40 \\times 0.25 = 10\\ \\text{g}$."}]},{"id":"99487d9c-23a0-4bbc-8e70-e5bd1f710998","cardType":"basic","points":1,"front":"How do you calculate the volume of solution?","back":"Use $V = \\dfrac{m}{c}$.","mcqOptions":[{"text":"Use $V = \\dfrac{m}{c}$.","correct":true,"explanation":"Rearranging $c = \\dfrac{m}{V}$ to make volume the subject gives $V = \\dfrac{m}{c}$. Mass and concentration must be expressed in compatible units."},{"text":"Use $V = \\dfrac{c}{m}$.","correct":false,"explanation":"This reverses the required ratio and gives incorrect units for volume. Rearranging the concentration equation gives $V = \\dfrac{m}{c}$."},{"text":"Use $V = m \\times c$.","correct":false,"explanation":"Multiplying mass by concentration does not isolate volume and produces unsuitable units. Volume is found by dividing mass by concentration: $V = \\dfrac{m}{c}$."},{"text":"Use $V = \\dfrac{1}{m \\times c}$.","correct":false,"explanation":"Taking the reciprocal of the product is not the correct algebraic rearrangement. From $c = \\dfrac{m}{V}$, multiplying by $V$ and dividing by $c$ gives $V = \\dfrac{m}{c}$."}]},{"id":"8a2507f9-a4dd-430f-aec8-a8713e96d06d","cardType":"basic","points":2,"front":"How does concentration depend on solute mass when volume is fixed?","back":"At fixed volume, concentration is directly proportional to solute mass.","mcqOptions":[{"text":"At fixed volume, concentration is directly proportional to solute mass.","correct":true,"explanation":"Because $c = \\dfrac{m}{V}$ and volume is fixed, concentration changes in the same ratio as solute mass. Doubling the mass doubles the concentration."},{"text":"At fixed volume, concentration is inversely proportional to solute mass.","correct":false,"explanation":"Inverse proportionality would mean concentration decreases when mass increases. With fixed volume, $c = \\dfrac{m}{V}$ shows that concentration increases directly with solute mass."},{"text":"At fixed volume, concentration is independent of solute mass.","correct":false,"explanation":"Changing solute mass changes the numerator in $c = \\dfrac{m}{V}$. With volume fixed, concentration therefore depends directly on solute mass."},{"text":"At fixed volume, concentration is proportional to the square of solute mass.","correct":false,"explanation":"The concentration equation contains solute mass to the first power, not squared. At fixed volume, concentration is directly proportional to solute mass."}]},{"id":"c89b35ea-643d-488f-8b65-95ac5ab73483","cardType":"basic","points":2,"front":"How does concentration depend on volume when solute mass is fixed?","back":"At fixed solute mass, concentration is inversely proportional to solution volume.","mcqOptions":[{"text":"At fixed solute mass, concentration is inversely proportional to solution volume.","correct":true,"explanation":"From $c = \\dfrac{m}{V}$, keeping mass fixed means increasing volume increases the denominator and reduces concentration. Doubling volume halves the concentration."},{"text":"At fixed solute mass, concentration is directly proportional to solution volume.","correct":false,"explanation":"Direct proportionality would make concentration increase with volume, but volume is in the denominator of $c = \\dfrac{m}{V}$. The relationship is inverse."},{"text":"At fixed solute mass, concentration is independent of solution volume.","correct":false,"explanation":"Changing the volume changes the denominator in $c = \\dfrac{m}{V}$, so concentration changes even when solute mass remains constant. The relationship is inverse."},{"text":"At fixed solute mass, concentration is proportional to the square of solution volume.","correct":false,"explanation":"Volume appears to the first power in the denominator, not as a square. Concentration decreases in inverse proportion to volume when solute mass is fixed."}]},{"id":"252fce12-ee90-4c79-9284-169f4b06c9f4","cardType":"cloze","points":null,"front":"Concentration is the mass of solute per unit [ ] of solution.","back":"Concentration is the mass of solute per unit volume of solution.","mcqOptions":[{"text":"volume","correct":true,"explanation":"Concentration measures the mass of dissolved solute in each unit volume of solution, commonly expressed in grams per cubic decimetre, g/dm³."},{"text":"mass","correct":false,"explanation":"Mass is tempting because concentration includes the solute’s mass, but this is divided by the solution’s volume. The missing term is volume."},{"text":"mole","correct":false,"explanation":"Moles can be used in molar concentration, but this definition specifically describes mass per unit volume of solution. The missing term is volume."},{"text":"density","correct":false,"explanation":"Density is mass per unit volume of a substance, whereas concentration is the mass of solute per unit volume of solution. The missing term is volume."}]},{"id":"cb8e90c4-c9bf-4e33-8da8-38cc369aea21","cardType":"cloze","points":null,"front":"One cubic decimetre equals $\\text{[...]}$.","back":"One cubic decimetre equals $\\boxed{1000\\ \\text{cm}^3}$.","mcqOptions":[{"text":"$$1000\\ \\text{cm}^3$","correct":true,"explanation":"A decimetre is 10 centimetres, so cubing the conversion gives $1\\ \\text{dm}^3=(10\\ \\text{cm})^3=1000\\ \\text{cm}^3$."},{"text":"$$100\\ \\text{cm}^3$","correct":false,"explanation":"This results from squaring the length conversion as though converting area. Volume requires cubing 10, so $1\\ \\text{dm}^3=1000\\ \\text{cm}^3$."},{"text":"$$10\\ \\text{cm}^3$","correct":false,"explanation":"This applies the linear conversion directly to a volume. Since all three dimensions are multiplied by 10, the correct volume is $1000\\ \\text{cm}^3$."},{"text":"$$0.001\\ \\text{cm}^3$","correct":false,"explanation":"This reverses the conversion factor. A cubic decimetre is larger than a cubic centimetre, so it contains $1000\\ \\text{cm}^3$, not a fraction of one."}]},{"id":"b1b6c300-b9a0-4487-8e70-4d7f15e188bf","cardType":"cloze","points":null,"front":"The concentration formula is $\\text{[...]}$.","back":"The concentration formula is $\\boxed{c = \\dfrac{m}{V}}$.","mcqOptions":[{"text":"$$c = \\dfrac{m}{V}$","correct":true,"explanation":"Concentration is the mass of dissolved solute divided by the volume of solution, so the formula is $c=m/V$."},{"text":"$$c = m \\times V$","correct":false,"explanation":"Multiplying mass by volume gives the wrong relationship and units. Concentration is found by dividing the solute mass by the solution volume: $c=m/V$."},{"text":"$$c = \\dfrac{V}{m}$","correct":false,"explanation":"This inverts the concentration relationship and produces volume per unit mass. The required quantity is mass per unit volume, so $c=m/V$."},{"text":"$$c = \\dfrac{m}{V^2}$","correct":false,"explanation":"Squaring the volume is an unnecessary extra step and gives incorrect units. Concentration uses the first power of volume, giving $c=m/V$."}]},{"id":"585e6f53-b887-4b45-aed1-6c36c1599c3f","cardType":"cloze","points":null,"front":"The formula for mass of solute is $\\text{[...]}$.","back":"The formula for mass of solute is $\\boxed{m = c \\times V}$.","mcqOptions":[{"text":"$$m = c \\times V$","correct":true,"explanation":"Rearranging $c=m/V$ by multiplying both sides by $V$ gives $m=c\\times V$, with concentration times volume producing the solute mass."},{"text":"$$m = \\dfrac{c}{V}$","correct":false,"explanation":"Dividing concentration by volume does not correctly rearrange $c=m/V$. Multiplying both sides by volume gives the correct formula $m=c\\times V$."},{"text":"$$m = \\dfrac{V}{c}$","correct":false,"explanation":"This incorrectly divides volume by concentration and gives incompatible units. Solute mass is calculated by multiplying concentration by solution volume: $m=c\\times V$."},{"text":"$$m = c + V$","correct":false,"explanation":"Concentration and volume have different units, so they cannot be added. Their product gives the mass of solute, using $m=c\\times V$."}]},{"id":"30524f51-bba1-4bae-aed0-cc20b838aa98","cardType":"cloze","points":null,"front":"The formula for volume of solution is $\\text{[...]}$.","back":"The formula for volume of solution is $\\boxed{V = \\dfrac{m}{c}}$.","mcqOptions":[{"text":"$$V = \\dfrac{m}{c}$","correct":true,"explanation":"Starting from $c=m/V$, multiplying by $V$ and dividing by $c$ isolates volume, giving $V=m/c$."},{"text":"$$V = m \\times c$","correct":false,"explanation":"Multiplying mass by concentration does not isolate volume and gives incorrect units. Rearranging $c=m/V$ correctly gives $V=m/c$."},{"text":"$$V = \\dfrac{c}{m}$","correct":false,"explanation":"This reverses the required division and produces the reciprocal of volume. The mass must be divided by concentration, so $V=m/c$."},{"text":"$$V = m + c$","correct":false,"explanation":"Mass and concentration have different units and cannot be added. Dividing mass by concentration cancels the mass unit and gives volume: $V=m/c$."}]},{"id":"f11e00d8-8a9d-441d-bcd4-04361a32b396","cardType":"cloze","points":null,"front":"$$30\\ \\text{g}$ dissolved to make $2\\ \\text{dm}^3$ gives a concentration of $\\text{[...]}$.","back":"$$30\\ \\text{g}$ dissolved to make $2\\ \\text{dm}^3$ gives a concentration of $\\boxed{15\\ \\text{g}/\\text{dm}^3}$.","mcqOptions":[{"text":"$$15\\ \\text{g}/\\text{dm}^3$","correct":true,"explanation":"Using $c=m/V$, divide $30\\ \\text{g}$ by $2\\ \\text{dm}^3$. This gives a concentration of $15\\ \\text{g}/\\text{dm}^3$."},{"text":"$$60\\ \\text{g}/\\text{dm}^3$","correct":false,"explanation":"This comes from multiplying 30 by 2 instead of dividing by the volume. Using $c=m/V$ gives $30/2=15\\ \\text{g}/\\text{dm}^3$."},{"text":"$$0.015\\ \\text{g}/\\text{dm}^3$","correct":false,"explanation":"This unnecessarily divides the result by 1000, despite the volume already being in dm³. Direct division gives $30/2=15\\ \\text{g}/\\text{dm}^3$."},{"text":"$$6.67\\ \\text{g}/\\text{dm}^3$","correct":false,"explanation":"This comes from reversing the division and then scaling the result incorrectly. Concentration requires mass divided by volume, giving $30/2=15\\ \\text{g}/\\text{dm}^3$."}]}]}],"examCountdown":{"examDate":"2027-05-17","paperLabel":"Paper 1"},"heading":"3.2.5 Concentration of solutions","title":"3.2.5 Concentration of solutions Flashcards","topbar":{"backHref":"/gcse/chemistry/aqa/flashcards"},"topicSidebar":"$L36"}]}],"topicId":"29f56736-6876-5985-8e24-bd7413d34b54","walled":"$L37"}],"$L38","$L39"]