Show that the equation 2log2x=log2(x+a)+32\log_2 x = \log_2(x + a) + 32log2x=log2(x+a)+3, can be expressed in the form x2−8x−8a=0x^2 - 8x - 8a = 0x2−8x−8a=0
Given the equation 2log2x=log2(x+a)+32\log_2 x = \log_2(x + a) + 32log2x=log2(x+a)+3 has only one real root find the value of aaa.