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Question 9

Given that k k\,k is a constant

a.

Find ∫(kx3+2x)dx\displaystyle \int \left( \frac{k}{x^3} + 2x \right) dx∫(x3k​+2x)dx Giving your answer in its simplest form.

[3]
b.

Find the value of k k\,k such that ∫12(kx3+2x)dx=12\displaystyle \int_1^2 \left( \frac{k}{x^3} + 2x \right) dx = 12∫12​(x3k​+2x)dx=12

[3]

Integration Questions

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