Show that the equation
1+cosx=3tanxsinx 1 + \cos x = 3 \tan x \sin x 1+cosx=3tanxsinxCan be written in the form
4cos2x+cosx−3=0 4\cos^2 x + \cos x - 3 = 0 4cos2x+cosx−3=0Hence solve, for 0≤x<360∘0 \leq x < 360^\circ0≤x<360∘, the equation,
1+cosx=3tanxsinx 1 + \cos x = 3 \tan x \sin x 1+cosx=3tanxsinxGive your answers to one decimal place where appropriate.