units of metres per second squared; the metres per second unit stated in the question is a speed unit."}]}],"generatedAt":"2026-07-20T16:31:10.164Z","modelVersion":"gpt-5.6-sol","explanationVersion":"v3"},"options":[]},{"id":"0923232c-4b49-4602-b291-e8dbc0893285","label":"b","content":"Find the distance AB.","markscheme":"- Use $s = \\left( \\frac{u+v}{2} \\right) t$ M1\n- $s = \\left( \\frac{50/9 + 175/9}{2} \\right) 10$ M1\n- $s = 125 \\text{ m}$ A1","marks":3,"order":1,"markingRubric":{"totalMarks":3,"points":[{"id":"p1","marks":1,"description":"Uses a valid suvat equation for distance.","code":"M"},{"id":"p2","marks":1,"description":"Substitutes values correctly.","code":"M"},{"id":"p3","marks":1,"description":"Obtains $125$.","code":"A"}],"finalAnswers":["125"],"generatedAt":"2026-05-12T02:14:06.558Z","modelVersion":"gemini-3-flash-preview"},"explanation":{"methods":[{"id":"average_velocity","label":"Use average velocity","steps":[{"type":"text","order":0,"title":"Convert the speeds","content":"The time is in seconds, so use metres per second for both speeds. Since $1\\text{ km/h}=\\frac{5}{18}\\text{ m/s}$,\n$$u=20\\times\\frac{5}{18}=\\frac{50}{9}\\text{ m/s},\\qquad v=70\\times\\frac{5}{18}=\\frac{175}{9}\\text{ m/s}.$$","highlights":[{"text":"Find the distance AB.","location":"specification"}]},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$s=\\left(\\frac{\\htmlData{anchor=mean}{\\color{@sky}{u+v}}}{2}\\right)\\htmlData{anchor=time}{\\color{@sky}{t}}$"},{"latex":"$$s=\\left(\\frac{\\htmlData{anchor=speeds}{\\color{@sky}{\\frac{50}{9}+\\frac{175}{9}}}}{2}\\right)10$"}]},"order":1,"title":"Use mean velocity","description":"For constant acceleration, distance equals mean velocity multiplied by time. The formula earns the first M1 mark; substituting the converted speeds earns the second M1 mark."},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$s=\\left(\\frac{\\htmlData{anchor=substitution}{\\frac{50}{9}+\\frac{175}{9}}}{2}\\right)10$"},{"latex":"$$s=\\htmlData{anchor=distance}{125\\text{ m}}$"}]},"order":2,"title":"Calculate the distance","description":"Evaluate the substitution to obtain the distance in metres. The correct final value earns the A1 mark."}]}],"generatedAt":"2026-07-20T16:35:01.260Z","modelVersion":"gpt-5.6-sol","explanationVersion":"v3"},"options":[]}],"options":[],"explanation":null,"firstAttemptFullMarks":{"percent":52}},{"id":"5fbab14f-57c7-46f0-803f-d32f41d14488","revisionId":"9c931b14-8271-4231-8a8c-6330113d0dff","questionNumber":"4","questionType":"LA","specification":"A stone is dropped from a point 120 m from the ground.","difficulty":2,"difficultyBand":"medium","totalMarks":6,"sourceTitle":"Question Set 1: Constant Acceleration","calculatorUse":null,"parts":[{"id":"1aa637e7-8ff7-461e-9127-236c6d46a9f2","label":"a","content":"Find the time it takes for the stone to reach the ground.","markscheme":"- Use $s = ut + \\frac{1}{2}at^2$ with $s=-120, u=0, a=-9.8$ M1\n- $-120 = -4.9t^2 \\implies t^2 = 24.48...$ M1\n- $t = 4.9 \\text{ s}$ (2sf) A1","marks":3,"order":0,"markingRubric":{"totalMarks":3,"points":[{"id":"p1","marks":1,"description":"Sets up $s = ut + 0.5at^2$ with $u=0$ and $a=9.8$ or $-9.8$.","code":"M"},{"id":"p2","marks":1,"description":"Solves for $t^2$.","code":"M"},{"id":"p3","marks":1,"description":"Obtains $4.9$ (accept $5.0$ if $g=10$ used).","code":"A"}],"finalAnswers":["4.9"],"generatedAt":"2026-05-12T02:14:06.558Z","modelVersion":"gemini-3-flash-preview"},"explanation":{"methods":[{"id":"suvat","label":"Use constant acceleration","steps":[{"type":"text","order":0,"title":"Choose a direction","content":"Take upwards as positive. The stone moves $120\\text{ m}$ downwards, so $s=-120\\text{ m}$. It is dropped, so its initial velocity is $u=0\\text{ m s}^{-1}$, and gravity gives $a=-9.8\\text{ m s}^{-2}$.","highlights":[{"text":"A stone is dropped from a point 120 m from the ground.","location":"specification"}]},{"type":"text","order":1,"title":"Choose the formula","content":"U

Constant Acceleration

Question 4

Constant Acceleration Questions

Constant Acceleration

Question 4

Constant Acceleration Questions