Show that the equation
3sin2xtan2x=cos2x+2 3\sin 2x \tan 2x = \cos 2x + 2 3sin2xtan2x=cos2x+2Can be written in the form
4cos22x+2cos2x−3=0 4\cos^2 2x + 2\cos 2x - 3 = 0 4cos22x+2cos2x−3=0Find all values for x x\,x in the interval 0≤x<180∘0 \leq x < 180^\circ0≤x<180∘, for which
3sin2xtan2x=cos2x+2 3\sin 2x \tan 2x = \cos 2x + 2 3sin2xtan2x=cos2x+2Give your answers to two decimal places.
Practise Edexcel AS Level Maths Trigonometric Identities and Equations with exam-style questions for AS Level Maths. 30 questions covering 10.1 Angles in all four Quadrants, 10.2 Exact Values of Trigonometric Ratios, 10.3 Trigonometric Identities, 10.4 Solving Trigonometric Equations, 10.5 Harder Trigonometric Equations, and 10.6 Equations and Identities, matched to the Edexcel AS Level Maths (8MA0) specification and written in Paper 1 and Paper 2 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.