Solve 6sin2θ=cosθ+46 \sin^2 \theta = \cos \theta + 46sin2θ=cosθ+4 giving all the solutions for the interval 0≤θ<360∘0 \leq \theta < 360^\circ0≤θ<360∘
Hence, solve 6sin22θ=cos2θ+46 \sin^2 2\theta = \cos 2\theta + 46sin22θ=cos2θ+4 giving all the solutions for the interval 0≤θ<360∘0 \leq \theta < 360^\circ0≤θ<360∘
41 exam-style questions on Edexcel AS Level Maths Trigonometric Identities and Equations, covering 10.1 Angles in all four Quadrants, 10.2 Exact Values of Trigonometric Ratios, 10.3 Trigonometric Identities, 10.4 Solving Trigonometric Equations, 10.5 Harder Trigonometric Equations, and 10.6 Equations and Identities. Each one has a worked solution and a mark scheme showing where the marks go.