The points A A\,A and B B\,B have coordinates (−1,k+2)(-1, k + 2)(−1,k+2) and (2k−3,8)(2k - 3, 8)(2k−3,8) where k k\,k is a constant.
Given the gradient of AB AB\,AB is 13\displaystyle \frac{1}{3}31
Show that k=4k = 4k=4
Find the equation of the line that passes through A A\,A and BBB.
Find the equation of the perpendicular bisector of AB AB\,AB and BBB. Give your answer in the form ax+by+c=0ax + by + c = 0ax+by+c=0
