Solve the equation sin2x=tan2x\sin^2 x = \tan^2 xsin2x=tan2x for 0∘≤x≤180∘0^\circ \leq x \leq 180^\circ0∘≤x≤180∘
Prove that 2sinx−cos2x+12+sinx≡sinx\displaystyle \frac{2 \sin x - \cos^2 x + 1}{2 + \sin x} \equiv \sin x2+sinx2sinx−cos2x+1≡sinx