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The ideal operational amplifier (A-level only)

What you'll learn:

  • What an operational amplifier (op-amp) is and how it connects to a circuit.
  • The two defining characteristics of an ideal op-amp.
  • How to use the open-loop transfer function to calculate output voltage.
  • How an op-amp functions as a simple comparator to make decisions in circuits.

The Op-Amp as a System Building Block

Inside a real operational amplifier, there are dozens of tiny transistors, resistors, and capacitors working together. Fortunately, in A-level Physics, we do not need to understand its internal circuitry.

Instead, we treat the op-amp as a system building block. This means we view it as a "black box" that performs a specific, reliable function. By combining op-amps with standard components like resistors and capacitors, we can easily build complex analogue signal processing circuits (like amplifiers, filters, and oscillators).

Signal and Power Connections

An op-amp is represented in circuit diagrams as a triangle pointing in the direction of signal flow (from left to right).

Op-amp symbol

There are five main connections you need to know:

  1. Inverting input (−-−): A signal applied here is amplified and inverted (flipped upside down or multiplied by a negative number).
  2. Non-inverting input (+++): A signal applied here is amplified but keeps its original polarity.
  3. Output (VoutV_{\text{out}}Vout​): The single pin where the processed signal leaves the op-amp.
  4. Positive power supply (+Vs+V_s+Vs​): Op-amps are active components; they need external power to work. This is typically connected to a positive DC voltage, like +15 V.
  5. Negative power supply (−Vs-V_s−Vs​): This is typically connected to a negative DC voltage, like -15 V, or sometimes to 0 V (ground).
Definition

Open-loop

"Open-loop" simply means there is no feedback connection in the circuit. The output is not wired back to either of the inputs. The op-amp is simply taking the inputs, doing its job, and sending the result directly to the output.

Characteristics of an Ideal Op-Amp

Real op-amps are incredibly complex and have minor imperfections. To make designing circuits easier, we use a theoretical model called the ideal op-amp. You must memorize its two main characteristics:

1. Infinite Input Resistance

The resistance between the two input terminals is assumed to be infinite.

  • Practical consequence: Absolutely zero current flows into or out of the inverting or non-inverting inputs. The op-amp "looks" at the voltage of the incoming signals without drawing any electrical current from them.

2. Infinite Open-Loop Gain

Gain is the multiplier by which an amplifier increases a signal. An ideal op-amp has an infinite open-loop gain.

  • Practical consequence: Any voltage difference between the two inputs, no matter how microscopically small, will be multiplied by infinity. In a real circuit, this causes the output voltage to instantly shoot up to the maximum possible value the power supply allows.
Key Idea

The Golden Rules of the Ideal Op-Amp

Whenever you analyze an op-amp circuit, start by reminding yourself:

  1. No current flows into the inputs.
  2. If it is in open-loop, a tiny difference in input voltages causes a huge output voltage.

The Open-Loop Transfer Function

For a real op-amp, the open-loop gain is not quite infinite, but it is typically extremely large (often around 10510^5105). We call this open-loop gain AOLA_{\text{OL}}AOL​.

The op-amp works by amplifying the difference between the voltages at its two inputs. This relationship is given by the open-loop transfer function:

Vout=AOL(V+−V−) V_{\text{out}} = A_{\text{OL}}(V_+ - V_-) Vout​=AOL​(V+​−V−​)
  • VoutV_{\text{out}}Vout​ is the output voltage.
  • AOLA_{\text{OL}}AOL​ is the open-loop gain (no units).
  • V+V_+V+​ is the voltage at the non-inverting input.
  • V−V_-V−​ is the voltage at the inverting input.

Saturation

An amplifier cannot create energy out of nowhere. The output voltage VoutV_{\text{out}}Vout​ can never exceed the power supply voltages (+Vs+V_s+Vs​ and −Vs-V_s−Vs​).

If the formula calculates a VoutV_{\text{out}}Vout​ that is greater than +Vs+V_s+Vs​, the op-amp simply outputs +Vs+V_s+Vs​. We say the op-amp is saturated.

Open-loop transfer characteristic

Notice how narrow the central diagonal line is. Because AOLA_{\text{OL}}AOL​ is so massive, even a tiny difference of a few microvolts between V+V_+V+​ and V−V_-V−​ is enough to drive the output firmly into saturation.

Example

Calculating Output Voltage

An operational amplifier has an open-loop gain of 2×1052 \times 10^52×105 and is powered by a ±15 V\pm 15\text{ V}±15 V supply. The voltage at the inverting input is 2.4000 V2.4000\text{ V}2.4000 V and the voltage at the non-inverting input is 2.4001 V2.4001\text{ V}2.4001 V.

Determine the output voltage.

  1. State the open-loop transfer function:
Vout=AOL(V+−V−) V_{\text{out}} = A_{\text{OL}}(V_+ - V_-) Vout​=AOL​(V+​−V−​)
  1. Identify the known values from the question:
AOL=2×105 A_{\text{OL}} = 2 \times 10^5 AOL​=2×105 V+=2.4001 V V_+ = 2.4001\text{ V} V+​=2.4001 V V−=2.4000 V V_- = 2.4000\text{ V} V−​=2.4000 V
  1. Substitute the values into the equation:
Vout=(2×105)(2.4001−2.4000) V_{\text{out}} = (2 \times 10^5)(2.4001 - 2.4000) Vout​=(2×105)(2.4001−2.4000) Vout=(2×105)(0.0001) V_{\text{out}} = (2 \times 10^5)(0.0001) Vout​=(2×105)(0.0001) Vout=20 V V_{\text{out}} = 20\text{ V} Vout​=20 V
  1. Check against the power supply limits. The supply is ±15 V\pm 15\text{ V}±15 V. Because 20 V20\text{ V}20 V is greater than 15 V15\text{ V}15 V, the op-amp will saturate.
  2. State the final answer: The op-amp saturates, so Vout=15 VV_{\text{out}} = 15\text{ V}Vout​=15 V.
Common Mistake

Watch your signs

Always strictly follow the order (V+−V−)(V_+ - V_-)(V+​−V−​). If V−V_-V−​ is larger than V+V_+V+​, the bracket becomes negative, and the op-amp will drive towards negative saturation (−Vs-V_s−Vs​).

The Op-Amp as a Comparator

Because the open-loop gain is so huge, an op-amp in an open-loop configuration acts essentially as a digital switch. It compares the two input voltages and makes a binary decision:

  • If V+>V−V_+ > V_-V+​>V−​, the output swings instantly to +Vs+V_s+Vs​ (positive saturation).
  • If V+<V−V_+ < V_-V+​<V−​, the output swings instantly to −Vs-V_s−Vs​ (negative saturation).

This specific application is called a comparator. Comparators are the heart of sensor circuits (like automated streetlights or thermostats). Usually, one input is connected to a fixed reference voltage, and the other is connected to a sensor (like a thermistor or LDR) in a potential divider.

Example

A Simple Thermostat Logic

An op-amp is configured as a comparator. The inverting input (−-−) is wired to a fixed reference voltage of 5 V5\text{ V}5 V. The non-inverting input (+++) is wired to a temperature sensor. The sensor outputs 4 V4\text{ V}4 V when the room is cold, and 6 V6\text{ V}6 V when the room is hot. The power supply is ±12 V\pm 12\text{ V}±12 V.

Explain the behavior of the output voltage as the room heats up.

  1. Identify the fixed reference voltage:
V−=5 V V_- = 5\text{ V} V−​=5 V
  1. Analyze the "cold" state:
V+=4 V V_+ = 4\text{ V} V+​=4 V

Since V+<V−V_+ < V_-V+​<V−​, the transfer function (V+−V−)(V_+ - V_-)(V+​−V−​) yields a negative number. 3. Determine the cold output: The op-amp saturates negatively.

Vout=−12 V V_{\text{out}} = -12\text{ V} Vout​=−12 V
  1. Analyze the "hot" state:
V+=6 V V_+ = 6\text{ V} V+​=6 V

Since V+>V−V_+ > V_-V+​>V−​, the transfer function (V+−V−)(V_+ - V_-)(V+​−V−​) yields a positive number. 5. Determine the hot output: The op-amp saturates positively.

Vout=+12 V V_{\text{out}} = +12\text{ V} Vout​=+12 V
  1. Conclusion: As the room heats up and the sensor voltage crosses the 5 V5\text{ V}5 V threshold, the output abruptly switches from −12 V-12\text{ V}−12 V to +12 V+12\text{ V}+12 V.
Exam technique

In the exam

  1. If a question asks you to define an ideal op-amp, always list both "infinite open-loop gain" and "infinite input resistance".
  2. When calculating VoutV_{\text{out}}Vout​ using the transfer function, your final step must always be to check the power supply limits. Examiners love to award a final mark for recognizing saturation.
  3. Pay close attention to the labels on the inputs. Sometimes diagrams draw the inverting input on the top, and sometimes on the bottom. Don't assume the top wire is always V+V_+V+​.
Self review

Check yourself

  • Can you draw the circuit symbol for an op-amp and accurately label all five main connections?
  • Why do we assume no current flows into the inputs of an ideal op-amp?
  • If an op-amp is powered by a ±9 V\pm 9\text{ V}±9 V supply and acts as a comparator, what are the two possible output voltages it will normally settle at?
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