What is the upward acceleration of the 2.0 kg probe at the instant the ballast block is released? (Take g=9.8 m s−2g = 9.8\text{ m s}^{-2}g=9.8 m s−2)
5.9 m s−25.9\text{ m s}^{-2}5.9 m s−2
9.8 m s−29.8\text{ m s}^{-2}9.8 m s−2
14.7 m s−214.7\text{ m s}^{-2}14.7 m s−2
24.5 m s−224.5\text{ m s}^{-2}24.5 m s−2
