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1 Unit 1: Pure Mathematics A

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Question 329

Given that y=2xy=2^xy=2x:

a.

Express 4x 4^x\,4x in terms of yyy.

[2]
b.

Hence solve the equation 4x−6(2x)−16=04^x-6(2^x)-16=04x−6(2x)−16=0.

[3]
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1 Unit 1: Pure Mathematics A Questions

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