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1 Unit 1: Pure Mathematics A

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Question 222

Solve, for −180°⩽θ<180°-180° \leqslant \theta < 180°−180°⩽θ<180°, the equation tan⁡(θ+30°)=−2.5\tan(\theta + 30°) = -2.5tan(θ+30°)=−2.5

Give your answers to 1 decimal place.

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1 Unit 1: Pure Mathematics A Questions

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