Given that sinθ≠±1\sin \theta \neq \pm 1sinθ=±1, prove the identity
11−sinθ+11+sinθ≡2sec2θ \frac{1}{1 - \sin \theta} + \frac{1}{1 + \sin \theta} \equiv 2 \sec^2 \theta 1−sinθ1+1+sinθ1≡2sec2θHence, find the set of values of kkk for which the equation
11−sinθ+11+sinθ=k \frac{1}{1 - \sin \theta} + \frac{1}{1 + \sin \theta} = k 1−sinθ1+1+sinθ1=khas real solutions. Fully justify your answer.
Given that θ\thetaθ is in the second quadrant (reflex angle between 90∘90^\circ90∘ and 180∘180^\circ180∘) and
11−sinθ+11+sinθ=10 \frac{1}{1 - \sin \theta} + \frac{1}{1 + \sin \theta} = 10 1−sinθ1+1+sinθ1=10find the exact value of tanθ\tan \thetatanθ.
225 exam-style questions on WJEC A Level Maths 3.5 Trigonometry (A-level only), covering 3.5.1 Trigonometry (A-level only), 3.5.2 Trigonometry (A-level only), 3.5.3 Trigonometry (A-level only), 3.5.4 Trigonometry (A-level only), 3.5.5 Trigonometry (A-level only), 3.5.6 Trigonometry (A-level only), 3.5.7 Trigonometry (A-level only), and 3.5.8 Trigonometry (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.