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2.7 Kinematics

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Question 27

The velocity of a particle moving in a straight line after t t\,t seconds is given by v=(6t−2t2)v = (6t - 2t^2)v=(6t−2t2) m s−1^{-1}−1.

When t=0t = 0t=0 the particle is at the point O O\,O on the line.

Find the distance of the particle from O O\,O at the instant it next comes to instantaneous rest.

[5]
Markscheme

2.7 Kinematics Questions

  1. A Level
  2. /Maths
  3. /2.7 Kinematics

102 exam-style questions on WJEC A Level Maths 2.7 Kinematics, covering 2.7.1 Kinematics, 2.7.2 Kinematics, 2.7.3 Kinematics, and 2.7.4 Kinematics. Each one has a worked solution and a mark scheme showing where the marks go.

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