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2.7 Kinematics

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Question 19

A particle moves in a straight line with acceleration a=(4t−6)a = (4t - 6)a=(4t−6) m s−2^{-2}−2 at time t t\,t seconds.

When t=0t = 0t=0 the velocity of the particle is 5 m s−1^{-1}−1.

Find the velocity of the particle when t=4t = 4t=4.

[4]
Markscheme

2.7 Kinematics Questions

  1. A Level
  2. /Maths
  3. /2.7 Kinematics

102 exam-style questions on WJEC A Level Maths 2.7 Kinematics, covering 2.7.1 Kinematics, 2.7.2 Kinematics, 2.7.3 Kinematics, and 2.7.4 Kinematics. Each one has a worked solution and a mark scheme showing where the marks go.

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