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2.7 Kinematics

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Question 15

A particle leaves O O\,O at time t=0t=0t=0 with velocity v=(3t+5−2t2) m s−1v=(3t+5-2t^2)\text{ m s}^{-1}v=(3t+5−2t2) m s−1.

a.

Find the value of t t\,t and the speed of the particle when it stops accelerating.

[4]
b.

Find the distance of the particle from O O\,O when it changes direction.

[4]
Markscheme

2.7 Kinematics Questions

  1. A Level
  2. /Maths
  3. /2.7 Kinematics

102 exam-style questions on WJEC A Level Maths 2.7 Kinematics, covering 2.7.1 Kinematics, 2.7.2 Kinematics, 2.7.3 Kinematics, and 2.7.4 Kinematics. Each one has a worked solution and a mark scheme showing where the marks go.

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