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2.7 Kinematics

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Question 5

A particle moves in a straight line with acceleration a=(3t+5) m s−2a=(3t+5)\text{ m s}^{-2}a=(3t+5) m s−2. At t=0t=0t=0 its velocity is 2 m s-1. At time t=Tt=Tt=T, its velocity is 6 m s-1.

a.

Show that 3T2+10T−8=03T^2+10T-8=03T2+10T−8=0.

[3]
b.

Determine TTT.

[2]
c.

Find the distance travelled between t=0t=0t=0 and t=Tt=Tt=T.

[3]
Markscheme

2.7 Kinematics Questions

  1. A Level
  2. /Maths
  3. /2.7 Kinematics

102 exam-style questions on WJEC A Level Maths 2.7 Kinematics, covering 2.7.1 Kinematics, 2.7.2 Kinematics, 2.7.3 Kinematics, and 2.7.4 Kinematics. Each one has a worked solution and a mark scheme showing where the marks go.

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