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1.6 Exponentials and logarithms

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Question 38
a.

Show that the equation 2log⁡2x=log⁡2(x+a)+32\log_2 x = \log_2(x + a) + 32log2​x=log2​(x+a)+3, can be expressed in the form x2−8x−8a=0x^2 - 8x - 8a = 0x2−8x−8a=0

[3]
b.

Given the equation 2log⁡2x=log⁡2(x+a)+32\log_2 x = \log_2(x + a) + 32log2​x=log2​(x+a)+3 has only one real root find the value of aaa.

[3]

1.6 Exponentials and logarithms Questions

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