Giving your answers to 2 decimal places, solve the simultaneous equations
e2y=x+1ln(x−2)=2y−1 \begin{aligned} e^{2y} &= x + 1 \\ \ln(x - 2) &= 2y - 1 \end{aligned} e2yln(x−2)=x+1=2y−1104 exam-style questions on WJEC A Level Maths 1.6 Exponentials and logarithms, covering 1.6.1 Exponentials and logarithms, 1.6.2 Exponentials and logarithms, 1.6.3 Exponentials and logarithms, 1.6.4 Exponentials and logarithms, 1.6.5 Exponentials and logarithms, 1.6.6 Exponentials and logarithms, 1.6.7 Exponentials and logarithms, 1.6.8 Exponentials and logarithms, and 1.6.9 Exponentials and logarithms. Each one has a worked solution and a mark scheme showing where the marks go.