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1.6 Exponentials and logarithms
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Question 13
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Giving your answers to 2 decimal places, solve the simultaneous equations
e2y=x+1ln(x−2)=2y−1 \begin{aligned} e^{2y} &= x + 1 \\ \ln(x - 2) &= 2y - 1 \end{aligned}
e
2
y
ln
(
x
−
2
)
=
x
+
1
=
2
y
−
1
[7]
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1.6 Exponentials and logarithms
