Differentiation

The point $K\,$ lies on the curve with equation $y=3ex+1ex+1\displaystyle y = \frac{3e^x+1}{e^x+1}$ with $x$ -coordinate 0.

Find an equation of the normal to the curve at the point $K$ .

[5]

The point $K\,$ lies on the curve with equation $y=3ex+1ex+1\displaystyle y = \frac{3e^x+1}{e^x+1}$ with $x$ -coordinate 0.

Find an equation of the normal to the curve at the point $K$ .

[5]

Differentiation Questions