A curve has the parametric equations
x=ln(2t+1),y=t2−16,t>−0.5 x = \ln(2t + 1), \quad y = t^2 - 16, \quad t > -0.5 x=ln(2t+1),y=t2−16,t>−0.5Find the points where the curve crosses the coordinate axes.
Find an equation for the tangent to the curve when t=1t = 1t=1.
