Solve, for 0<x<π0 < x < \pi0<x<π, the equation
(4x−5)(4sin2x−3)=0 (4x - 5)(4\sin^2 x - 3) = 0 (4x−5)(4sin2x−3)=0giving your answers in terms of π\piπ where appropriate.
Solve, for 0<θ<360∘0 < \theta < 360^\circ0<θ<360∘, the equation
11cosθ=3cos2θ+8 11\cos \theta = 3\cos 2\theta + 8 11cosθ=3cos2θ+8giving your answers to one decimal place.