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Trigonometric Functions

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Question 9
a.

Use the identity cos⁡2θ+sin⁡2θ=1\cos^2\theta + \sin^2\theta = 1cos2θ+sin2θ=1 to prove that 1+tan⁡2θ=sec⁡2θ1 + \tan^2\theta = \sec^2\theta1+tan2θ=sec2θ

[2]
b.

Solve, for 0≤θ≤3600 \leq \theta \leq 3600≤θ≤360, the equation,

2tan⁡2θ−3sec⁡θ=0 2\tan^2\theta - 3\sec\theta = 0 2tan2θ−3secθ=0

Give your answers to 1 decimal place.

[5]

Trigonometric Functions Questions

  1. A Level
  2. /Maths
  3. /Trigonometric Functions